Python重命名文件从csv文件读取名称 [英] Python rename files reading names from csv file
问题描述
您好,我一直在尝试适应这对我的需要,但我只是一个新的python,我有一个csv文件与多列和行,重要的列是1 =旧的文件名称,和2 =文件的新名称,所以我需要去到csv文件中列出的文件所在的目录,并将它们重命名为列2的新名称,因为我说我试过很多事情没有成功,我粘贴了最后一个代码,所以你有一个想法:
import os,unicodecsv as csv,sys
IDs = {}
#open并将csv文件
与open('documentos_corpus_ladino.csv','rb')一起存储为csvfile:
timeReader = csv.reader(csvfile,delimiter =',')
#构建一个带有相关ID的字典
for rowReader:
IDs [row [0]] = row [1]
#文件列表
path ='txt_orig /'
tmpPath ='txt_tmp /'
在os.listdir('txt_orig /')中的文件名:
oldname = filename
newname = filename.replace(oldname,csvfile.next()。rstrip()。split(,)[1]
os.rename(path + filename,tmpPath + newname)
非常感谢。
解决方案这将重命名每个匹配的文件,并报告尝试重命名的任何错误。它不会尝试移动不存在的文件。
import os,unicodecsv as csv
#打开并存储csv文件
IDs = {}
with open('documentos_corpus_ladino.csv','rb')as csvfile:
timeReader = csv.reader(csvfile,delimiter =',')
#构建具有相关标识的字典
for timeReader:
IDs [row [0]] = row [1]
#移动文件
path ='txt_orig /'
tmpPath ='txt_tmp /'
对于os.listdir(路径)中的oldname:
#忽略路径中不在csv文件中的文件
如果ID中的oldname:
try:
os.rename(os.path.join(path,oldname),os.path.join(tmpPath,IDs [oldname]))
except:
print 'file'+ oldname +'无法重命名为'+ IDs [oldname] +'!'
Hi there i've been trying to adapt this to my needs but I'm just a newbe in python, I have a csv file with multiple columns and rows, important columns are 1 = old name of file, and 2 = new name of file, so I need to go the directory where the files listed in csv file are and rename them to the new name of column 2, as I say I've tried many things without success, I paste the last code I've made so you have an idea:
import os, unicodecsv as csv, sys IDs = {} #open and store the csv file with open('documentos_corpus_ladino.csv','rb') as csvfile: timeReader = csv.reader(csvfile, delimiter = ',') # build a dictionary with the associated IDs for row in timeReader: IDs[ row[0] ] = row[1] # #get the list of files path = 'txt_orig/' tmpPath = 'txt_tmp/' for filename in os.listdir('txt_orig/'): oldname = filename newname = filename.replace(oldname, csvfile.next().rstrip().split(",")[1]) os.rename(path + filename, tmpPath + newname)
Thanks a lot.
解决方案This will rename each matching file, and report any errors trying to rename. It will not attempt to move non-existent files.
import os, unicodecsv as csv # open and store the csv file IDs = {} with open('documentos_corpus_ladino.csv','rb') as csvfile: timeReader = csv.reader(csvfile, delimiter = ',') # build dictionary with associated IDs for row in timeReader: IDs[row[0]] = row[1] # move files path = 'txt_orig/' tmpPath = 'txt_tmp/' for oldname in os.listdir(path): # ignore files in path which aren't in the csv file if oldname in IDs: try: os.rename(os.path.join(path, oldname), os.path.join(tmpPath, IDs[oldname])) except: print 'File ' + oldname + ' could not be renamed to ' + IDs[oldname] + '!'
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