PHP解析.dat文件 [英] PHP Parsing a .dat file

问题描述

我有一个.dat文件本质上;分隔文件，我试图将其转换为制表符分隔的.txt。我不确定的问题是，新文件的每一行将是原始文件的行的3个组合，每个原始行有不同数量的数据。第一列只标识分组中的每一行。

I have a .dat file that is essentially ; delimited file and I'm trying to convert it to a tab delimited .txt. The problem that I am not sure about is that each row of the new file will be a combination of 3 of the original file's rows, each original row has a different quantity of data. The first column just identifies each row in a grouping. What would be the best way to do this?

取得原始资料：

01;zxc;asd;qwe;uio;jkl;asd;123;456
02;lkj;oiu;oji
03;fjifao;vbofekjf;fjieofk;aoijf;voien3984
01;lkj;oiu;fji;eoj;vnk;fji;098;321
02;fji;oje;jvi
03;jie;voi;djv;eojf;38723

结束输出：

zxc   asd   qwe   uio   jkl   asd   123   456   lkj   oiu   oji   fjifao   vbofekjf   fjieofk   aoijf   voien3984
lkj   oiu   fji   eoj   vnk   fji   098   321   fji   oje   jvi   jie   voi   djv   eojf   38723

任何想法？

推荐答案

$lines = file($data);
$rows = array();
$row_pivot = -1;
foreach ($lines as $line) {

    // Split line by ;
    $data = explode(';', trim($line));

    // Get the first element
    $r_id = array_shift($data);
    if ($r_id == '01') {
        // When 01 is the first element, start a new row
        // You can dump the previous row here as well if you aim for speed
        $row_pivot++;
        $rows[$row_pivot] = array();
    }

    // Add data to row
    $rows[$row_pivot] = array_merge($rows[$row_pivot], $data);
}

// Print rows
foreach ($rows as $r) {
    echo implode("\t", $r)."\n";
}

这篇关于PHP解析.dat文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！