调试jQuery的处理程序 [英] Debugging jquery handlers

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本文介绍了调试jQuery的处理程序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

此问题是<一后随href="http://stackoverflow.com/questions/33110233/$p$pventing-jquery-ajax-call-from-sending-form-data-twice">this一。我创建href="https://jsfiddle.net/8g0rvgnt/5/" rel="nofollow">简单的例子来检查有code是处理程序中执行的

This question is a followup of this one. I have created a simple example to check how code is executed within the handler. For the form

<form id="calendar_id" method="post">
    Insert date: <input id="date_id" type="text" name="l_date" required>
</form>

我尝试使用下面的JavaScript来检索字段:

I'm trying to retrieve the fields using the following javascript:

function get_form_data_uid($form) {
    var unindexed_array = $form.serializeArray();
    var indexed_array = {};

    $.map(unindexed_array, function (n, i) {
        indexed_array[n['name']] = n['value'];
    });

    indexed_array['uid'] = 'badbfadbbfi';

    return indexed_array;
}

$("#calendar_id").submit(function (e) {
    var uri, method, formId, $form, form_data;
    // Prevent default submit
    e.preventDefault();
    e.stopImmediatePropagation();

    uri = "/";
    method = "POST";
    formId = "#calendar_id";

    $form = $(formId);
    form_data = get_form_data_uid($form);

    alert("form_data " + form_data);

    // Set-up ajax call
    var request = {
        url: uri,
        type: method,
        contentType: "application/json",
        accepts: "application/json",
        cache: false,
        // Setting async to false to give enough time to initialize the local storage with the "token" key
        async: false,
        dataType: "json",
        data: form_data
    };
    // Make the request
    $.ajax(request).done(function (data) { // Handle the response
        // Attributes are retrieved as object.attribute_name
        console.log("Data from change password from server: " + data);
        alert(data.message);
    }).fail(function (jqXHR, textStatus, errorThrown) { // Handle failure
        console.log(JSON.stringify(jqXHR));
        console.log("AJAX error on changing password: " + textStatus + ' : ' + errorThrown);
    });

});

然而,不执行该处理程序中的code(警报未示出)。为什么?

However, the code within the handler is not executed (the alert is not shown). Why?

编辑:

在code工作的jsfiddle 但不是在Firefox浏览器。

The code works jsfiddle but not in firefox.

推荐答案

至少,你调用一个函数 get_form_data_with_token()这是没有定义在贴$随时随地C $℃。也许你的意思是打电话给你的 get_form_data_uid()

At least, you are calling a function get_form_data_with_token() which is not defined anywhere in your posted code. Perhaps you meant to call your get_form_data_uid().

会刚刚作出了这样的评论,但显然不能。

Would have just made this a comment, but apparently cannot.

这篇关于调试jQuery的处理程序的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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