cudaDeviceSynchronize在启动后返回错误代码4 [英] cudaDeviceSynchronize returned error code 4 after launching

问题描述

我使用CUDA编写了一个简单的矩阵乘法代码，当我为 A（10000 * 10000）* B（10000 * 10000）接收此消息：

I have written a simple matrix multiplication code using CUDA, when I run code for input size of A(10000*10000)*B(10000*10000), I receive this message:

cudaDeviceSynchronize returned error code 4 after launching

在添加这些说明以测量运行时间后，我收到未指定的启动失败错误。

After adding these instructions in order to measure run time, I recieve "unspecified launch failure" error.

cudaEventRecord(start);
// here is my kernel call
cudaEventRecord(stop);
cudaEventSynchronize(stop); 

这是我的内核调用：

mulKernel<<<1, dataSet.threadSize>>>(dev_c, dev_a, dev_b, dataSet.n, dataSet.m, dataSet.p, dataSet.threadSize);

这是我的内核代码：

    int i = threadIdx.x;
    int j, k, sum;
    //if(n<=threadSize)
    for(; i < n; i+=threadSize){
        for(j = 0; j < p; j++){
            sum = 0;
            for(k = 0; k < m; k++){
                sum += A[i * m + k] * B[k * p + j];
            }
            C[i *p + j] = sum;
        }
    }

如何解决此错误？

How can I fix this error?

推荐答案

您正在启动大小为 dataSet.threadSize 的1个块。这将是方式超过一个块中的最大线程数（对于Kepler GPU，我认为是1024）。阅读更多这里了解如何选择您的网格和块尺寸。

You are launching 1 block with size dataSet.threadSize. This would be way more than the maximum number of threads in a block (1024 for Kepler GPU I think). Read more here on how to choose your grid and block dimensions.

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