在CURL中展开变量 [英] expanding variable in CURL

问题描述

以下curl语句在我的shell脚本中正常工作。

  curl -Ld'username = user& password = password& source = oksoft& dmobile ='$ mnumber'& message = Slave正在运行OK'http://167.123.129.195/smsclient//api.php 
  

手机号码按预期展开。但是当我使用一个变量作为消息参数时，我得到$ myvar输出而不是展开的变量。

  curl -Ld' username = user& password = password& source = oksoft& dmobile ='$ mnumber'& message =$ myvar'http：//167.123.129.195/smsclient//api.php 
 
解决方案
 
 
 
 
 div> 
单引号抑制扩展。切换引号。
  curl ...'...'$ myvar'...'。 .. 
  
 
The following curl statement works OK in my shell script.
curl -Ld'username=user&password=password&source=oksoft&dmobile='$mnumber'&message=Slave is working OK' http://167.123.129.195/smsclient//api.php
The Mobile number is expanded as expected. But when I use a variable for the message parameter, I get $myvar output instead of the expanded variable.
curl -Ld'username=user&password=password&source=oksoft&dmobile='$mnumber'&message="$myvar"' http://167.123.129.195/smsclient//api.php
How do I use the variable for the message?
解决方案
Single quotes inhibit expansion. Switch up the quotes.
curl ...'..."'"$myvar"'"...'...


                        
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