使用D3.js为每个数据成员附加多个非嵌套元素 [英] Appending multiple non-nested elements for each data member with D3.js

问题描述

我想使用d3创建多个非嵌套元素，以创建如下所示的结构：

I would like to create multiple non-nested elements using d3 to create a structure like this:

    <div id="parent">
        <p> from data[0] </p>
        <p> from data[0] </p>

        <p> from data[1] </p>
        <p> from data[1] </p>

        <p> from data[2] </p>
        <p> from data[2] </p>
    </div>

创建嵌套结构会像

    d3.select('#parent').selectAll('p').data(data).enter().
           append('p')...append('p')

想要保持原始选择，即使在追加之后，因此我可以继续追加到父元素。谢谢！

but I would like to maintain the original selection even after the append, so I could continue appending to the parent element. Thank you!

推荐答案

使用嵌套的
$ b

The idomatic way of doing is with nesting:

var divs = d3.select('#parent').selectAll('p').data(data).enter().append('div');

divs.append('p')
divs.append('p')

其创建：

<div id="parent">
  <div>
    <p> from data[0] </p>
    <p> from data[0] </p>
  </div>

  <div>
    <p> from data[1] </p>
    <p> from data[1] </p>
  </div>

  <div>
    <p> from data[2] </p>
    <p> from data[2] </p>
  </div>
</div>

如果这不起作用，请保存您的选择并重复附加：

If that won't work, save your selection and repeatedly append:

var enterSelection = d3.select('#parent').selectAll('p').data(data).enter();

enterSelection.append('p')
enterSelection.append('p')

然后排序您添加的内容：

then sort what you've added:

d3.select('#parent').selectAll('p').sort(function(a, b){ return a.index - b.index; })

您需要为描述排序顺序的 data 的每个元素添加 index 属性。正常 i 仅在特定选择的上下文中定义，当我们重新选择时会丢失。

You'll need to add an index property to each element of data that describes the sort order. The normal i is only defined in the context of a particular selection, which is lost when we reselect.

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