消除D3基线图中的突然添加/删除 [英] Eliminate sudden additions/deletions in D3 basis line chart transition
本文介绍了消除D3基线图中的突然添加/删除的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有完全类似的SO问题
一个区别是,我有线插值为基础
var line = d3.svg.line()interpolate('basis')
$正在13小时内挣扎:/ please help
=snippetdata-lang =jsdata-hide =falsedata-console =truedata-babel =false> < html> < head> < title>图表< / title> < style>路径{stroke:#f00; } .line {stroke:#0f0; fill:none; stroke-width:2px; } .rule {stroke:#ccc; stroke-width:1px; }< / style> < / head> < body> < p>我想获得下面的图表,以使线条上的点显示为上下移动,而不是左右移动。 < / p> < p>当转换到更小的数据集时,我希望在线形成之前不会出现白色间隙。 < / p> < p>此外,网格线应滑入和滑出存在,而不是出现或消失。想法? < / p> < script src =http://d3js.org/d3.v2.min.js>< / script> < script> var data = [[1,8,8,8,8,8,8,8,8,8,8,8,8,8,8],[8,1,1,1,1,1,1 ,1,1,1,1,1,1,1,1],]; var data3 = [[1,1,1],[8,8,8],]; var w = 500,h = 100; var chart = d3.select('body')。append('div').attr('class','chart').append('svg:svg').attr('width',w).attr 'height',h); var color = d3.scale.category10(); //将路径插值器添加到d3 d3.interpolators.push(function(a,b){debugger; var isPath,isArea,interpolator,ac,bc,an,bn,d; //创建一个给定长度的新数组,填充它给定的值函数fill(value,length){return d3.range(length).map(function(){return value;});} //从路径字符串中提取坐标数组extractCoordinates ){return path.substr(1,path.length - (isArea?2:1))。split('L');} //从坐标数组创建一个路径function makePath + coordinate.join('L')+(isArea?'Z':'');} //用相同位置的坐标缓冲较小的路径function bufferPath(p1,p2){var d = p2.length - p1 .length; if(isArea){return fill(p1 [0],d / 2).concat(p1,fill(p1 [p1.length-1],d / 2)); } else {return fill(p1 [0],d).concat(p1); }} isPath = /M-?\d*\.?\d*,-?\d*\.?\d*(L-?\d*\.?\d *, - ?\d * \。?\d *)* Z?/; if(isPath.test(a)&& isPath.test(b)){isArea = a [a.length-1] ==='Z'; ac = extractCoordinates(a); bc = extractCoordinates(b); an = ac.length; bn = bc.length; if(an> bn){bc = bufferPath(bc,ac); } if(bn> an){ac = bufferPath(ac,bc); } //使用缓冲的路径创建一个interpolater(如果两个路径都有相同的长度,//函数将会成为默认字符串interpolator)interpolator = d3.interpolateString(bn> an?makePath(ac):a ,bn?makePath(bc):b); //如果结束值已更改,请确保最终的内插值正确返回bn>一个? interpolator:function(t){return t === 1? b:内插器(t); }; }}); function drawdata(data,chart){var num = data [0] .length-1; var x = d3.scale.linear()。domain([0,num])。range([0,w]); var y = d3.scale.linear()。domain([0,10])。range([h,0]); var line = d3.svg.line()。interpolate('basis').x(function(d,i){return x(i);} ); var flat = d3.svg.line().x(function(d,i){return x(i);}).y(y(-1)); var lines = chart.selectAll('。line').data(data); lines.enter()。append('path').attr('class','line').style('stroke',function(d,i){return color(i);}).attr ',line); lines.transition().ease('linear').duration(500).attr('d',line); lines.exit()。remove(); // legend var ticks = chart.selectAll('line').data(x.ticks(num)); ticks.enter()。append('line').attr('x1',x).attr('x2',x).attr('y1',0).attr('y2',h).attr ('class','rule'); ticks.transition().ease('linear').duration(500).attr('x1',x).attr('x2',x).attr('y1',0).attr('y2' , H); ticks.exit()。remove(); } var dats = [data,data3]; function next(){var it = dats.shift(); dats.push(it); drawdata(it,chart); } setInterval(next,2000);下一个(); < / script> < / body>< / html
解决方案 我相信d3有一个更干净的解决方案。请参阅 d3.svg.axis
。
var points0 = [[1,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8],[8,1,1,1, 1,1,1,1,1,1,1,1,1,1],]; var points1 = [[1,1,1],[8,8,8],]; var w = 500,h = 100; var chart = d3.select('body')。append('div').attr('class','chart').append('svg').attr('width',w ).attr('height',h)var color = d3.scale.category10(); function drawdata(data,svg){var num = data [0] .length-1; var x = d3.scale.linear()。domain([0,num])。range([0,w]); var y = d3.scale.linear()。domain([0,10])。range([h,0]); var line = d3.svg.line()。interpolate('basis').x(function(d,i){return x(i);} ); var flat = d3.svg.line().x(function(d,i){return x(i);}).y(y(-1)); var lines = chart.selectAll('path.line').data(data); line .enter().append('path').attr('class','line').style('stroke',(d,i)=> color(i))lines // .attr d',line).transition().ease('linear').duration(500).attrTween(d,function(d){return pathTween(line(d),4,this)})lines .exit () 。去掉(); // legend var ticks = chart.selectAll('line').data(x.ticks(num)); ticks.enter().append('line').attr('x1',w + 10)// HACK .attr('x2',w + 10)// HACK .attr('y1',0)。 attr('y2',h).attr('class','rule')ticks.transition().ease('linear').duration(500).attr('x1',x).attr ',x).attr('y1',0).attr('y2',h)ticks.exit()。remove();} const data = [points0,points1] setInterval()=& point = data [0] data.reverse()drawdata(point,chart)},1e3); function pathTween(d1,precision,path0){var path1 = path0.cloneNode(),n0 = path0.getTotalLength =(path1.setAttribute(d,d1),path1).getTotalLength(); //根据指定的精度对距离进行均匀采样。 var distance = [0],i = 0,dt = precision / Math.max(n0,n1);而((i + = dt)<1){距离.push(i); }距离.push(1); //在每个距离处计算点插值器。 var points = distance.map(function(t){var p0 = path0.getPointAtLength(t * n0),p1 = path1.getPointAtLength(t * n1); return d3.interpolate([p0.x,p0.y] [p1.x,p1.y]);});返回函数(t){returnM+ points.map(function(p){return p(t);})join(L); }; }
path {stroke:#f00;}。 stroke:#0f0; fill:none; stroke-width:2px;}。rule {stroke:#ccc; stroke-width:1px;}
< script src = https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js\"> ;</script>
I have exactly similar SO question
Eliminate sudden additions/deletions in D3 line chart transition
One difference is that, I have line interpolated as "basis"
var line = d3.svg.line().interpolate('basis')
Struggling with this exactly 13 hours :/ please help
<html>
<head>
<title>Chart</title>
<style>
path {
stroke: #f00;
}
.line {
stroke: #0f0;
fill: none;
stroke-width: 2px;
}
.rule {
stroke: #ccc;
stroke-width: 1px;
}
</style>
</head>
<body>
<p>I want to get the chart below to transition such that
the points on the lines appear to move up and down, not
side to side.
</p>
<p>When transitioning to the smaller data-set especially,
I'd like to not have a white gap appear before the lines
take shape.
</p>
<p>Also, the grid-lines should slide into and out of
existence, rather than appearing or disappearing. Ideas?
</p>
<script src="http://d3js.org/d3.v2.min.js"></script>
<script>
var data = [
[1,8,8,8,8,8,8,8,8,8,8,8,8,8,8],
[8,1,1,1,1,1,1,1,1,1,1,1,1,1,1],
];
var data3 = [
[1,1,1],
[8,8,8],
];
var w = 500,
h = 100;
var chart = d3.select('body').append('div')
.attr('class', 'chart')
.append('svg:svg')
.attr('width', w)
.attr('height', h);
var color = d3.scale.category10();
// Add path interpolator to d3
d3.interpolators.push(function(a, b) {
debugger;
var isPath, isArea, interpolator, ac, bc, an, bn, d;
// Create a new array of a given length and fill it with the given value
function fill(value, length) {
return d3.range(length)
.map(function() {
return value;
});
}
// Extract an array of coordinates from the path string
function extractCoordinates(path) {
return path.substr(1, path.length - (isArea ? 2 : 1)).split('L');
}
// Create a path from an array of coordinates
function makePath(coordinates) {
return 'M' + coordinates.join('L') + (isArea ? 'Z' : '');
}
// Buffer the smaller path with coordinates at the same position
function bufferPath(p1, p2) {
var d = p2.length - p1.length;
if (isArea) {
return fill(p1[0], d/2).concat(p1, fill(p1[p1.length - 1], d/2));
} else {
return fill(p1[0], d).concat(p1);
}
}
isPath = /M-?\d*\.?\d*,-?\d*\.?\d*(L-?\d*\.?\d*,-?\d*\.?\d*)*Z?/;
if (isPath.test(a) && isPath.test(b)) {
isArea = a[a.length - 1] === 'Z';
ac = extractCoordinates(a);
bc = extractCoordinates(b);
an = ac.length;
bn = bc.length;
if (an > bn) {
bc = bufferPath(bc, ac);
}
if (bn > an) {
ac = bufferPath(ac, bc);
}
// Create an interpolater with the buffered paths (if both paths are of the same length,
// the function will end up being the default string interpolator)
interpolator = d3.interpolateString(bn > an ? makePath(ac) : a, an > bn ? makePath(bc) : b);
// If the ending value changed, make sure the final interpolated value is correct
return bn > an ? interpolator : function(t) {
return t === 1 ? b : interpolator(t);
};
}
});
function drawdata(data, chart) {
var num = data[0].length-1;
var x = d3.scale.linear().domain([0, num]).range([0,w]);
var y = d3.scale.linear().domain([0, 10]).range([h, 0]);
var line = d3.svg.line().interpolate('basis')
.x(function(d, i) { return x(i); })
.y(function(d) { return y(d); });
var flat = d3.svg.line()
.x(function(d, i) { return x(i); })
.y(y(-1));
var lines = chart.selectAll('.line')
.data(data);
lines.enter().append('path')
.attr('class', 'line')
.style('stroke', function(d,i) { return color(i); })
.attr('d', line);
lines.transition()
.ease('linear')
.duration(500)
.attr('d', line);
lines.exit().remove();
// legend
var ticks = chart.selectAll('line')
.data(x.ticks(num));
ticks.enter().append('line')
.attr('x1', x)
.attr('x2', x)
.attr('y1', 0)
.attr('y2', h)
.attr('class', 'rule');
ticks.transition()
.ease('linear')
.duration(500)
.attr('x1', x)
.attr('x2', x)
.attr('y1', 0)
.attr('y2', h);
ticks.exit().remove();
}
var dats = [data, data3];
function next() {
var it = dats.shift();
dats.push(it);
drawdata(it, chart);
}
setInterval(next, 2000);
next();
</script>
</body>
</html
解决方案 I belive that d3 have a more clean solution. See d3.svg.axis
.
var points0 = [
[1,8,8,8,8,8,8,8,8,8,8,8,8,8,8],
[8,1,1,1,1,1,1,1,1,1,1,1,1,1,1],
];
var points1 = [
[1,1,1],
[8,8,8],
];
var w = 500,
h = 100;
var chart = d3.select('body').append('div')
.attr('class', 'chart')
.append('svg')
.attr('width', w)
.attr('height', h)
var color = d3.scale.category10();
function drawdata(data, svg) {
var num = data[0].length-1;
var x = d3.scale.linear().domain([0, num]).range([0,w]);
var y = d3.scale.linear().domain([0, 10]).range([h, 0]);
var line = d3.svg.line().interpolate('basis')
.x(function(d, i) { return x(i); })
.y(function(d) { return y(d); });
var flat = d3.svg.line()
.x(function(d, i) { return x(i); })
.y(y(-1));
var lines = chart.selectAll('path.line')
.data(data);
lines
.enter()
.append('path')
.attr('class', 'line')
.style('stroke', (d,i) => color(i))
lines
// .attr('d', line)
.transition()
.ease('linear')
.duration(500)
.attrTween("d", function(d) { return pathTween(line(d), 4, this)})
lines
.exit()
.remove();
// legend
var ticks = chart.selectAll('line')
.data(x.ticks(num));
ticks.enter()
.append('line')
.attr('x1', w+10) // HACK
.attr('x2', w+10) // HACK
.attr('y1', 0)
.attr('y2', h)
.attr('class', 'rule')
ticks.transition()
.ease('linear')
.duration(500)
.attr('x1', x)
.attr('x2', x)
.attr('y1', 0)
.attr('y2', h)
ticks.exit().remove();
}
const data = [points0, points1]
setInterval(() => {
const point = data[0]
data.reverse()
drawdata(point, chart)
}, 1e3);
function pathTween(d1, precision, path0) {
var path1 = path0.cloneNode(),
n0 = path0.getTotalLength(),
n1 = (path1.setAttribute("d", d1), path1).getTotalLength();
// Uniform sampling of distance based on specified precision.
var distances = [0], i = 0, dt = precision / Math.max(n0, n1);
while ((i += dt) < 1) {
distances.push(i);
}
distances.push(1);
// Compute point-interpolators at each distance.
var points = distances.map(function(t) {
var p0 = path0.getPointAtLength(t * n0),
p1 = path1.getPointAtLength(t * n1);
return d3.interpolate([p0.x, p0.y], [p1.x, p1.y]);
});
return function(t) {
return "M" + points.map(function(p) { return p(t); }).join("L");
};
}
path {
stroke: #f00;
}
.line {
stroke: #0f0;
fill: none;
stroke-width: 2px;
}
.rule {
stroke: #ccc;
stroke-width: 1px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
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