R:子集上的数据表,不包括值 [英] R: Data.table on subset excluding by value

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问题描述

使用 data.table R ,我试图对子集排除所选元素。我使用 by 运算符,但我不知道这是否是正确的方法。

Using data.table in R, I'm trying to make an operation on the subset excluding selected element. I'm using the by operator, but I don't know if this is the right approach.

这里有一个例子。例如。在 IAH:SNA 中的 Delta 的值为(3 + 3)/ 2,其是停止在 IAH:SNA 一次 Delta >

Here's an example. E.g. the value for Delta in IAH:SNA is (3+3)/2 which is the mean of Stops in IAH:SNA once Delta has been excluded.

library(data.table)
s1 <- "Market   Carrier Stops
IAH:SNA     Delta     1
IAH:SNA     Delta     1
IAH:SNA Southwest     3
IAH:SNA Southwest     3
MSP:CLE Southwest     2
MSP:CLE Southwest     2
MSP:CLE  American     2
MSP:CLE   JetBlue     1"

d <- data.table(read.table(textConnection(s1), header=TRUE))

setkey(d, Carrier, Market)

f <- function(x, y){
         subset(d, !(Carrier %in% x) & Market == y, Stops)[, mean(Stops)]}

d[, s := f(.BY[[1]], .BY[[2]]), by=list(Carrier, Market)]

##     Market   Carrier Stops     s
## 1: MSP:CLE  American     2  1.666667
## 2: IAH:SNA     Delta     1  3.000000
## 3: IAH:SNA     Delta     1  3.000000
## 5: IAH:SNA Southwest     3  1.000000
## 6: IAH:SNA Southwest     3  1.000000
## 7: MSP:CLE Southwest     2  1.500000
## 8: MSP:CLE Southwest     2  1.500000

上述解决方案< (它本质上是一个 mapply ),但我不知道如何做一个快速的 data.table 样的方式。

The above solution performs very poorly on large data sets (it's essentially an mapply), but I'm not sure how to do it in a fast data.table-like way.

也许可以(动态地)产生一个这样的因素?我只是不知道如何。 。 。

Perhaps one could (dynamically) generate a factor that does this? I'm just not sure how. . .

有办法改善吗?

编辑:只是为了它,这里是一个方法来获得上面的更大的版本

Just for the heck of it, here's a way to get a bigger version of the above

library(data.table)
dl.dta <- function(...){
      ## input years ..
      years <- gsub("\\.", "_", c(...))
      baseurl <- "http://www.transtats.bts.gov/Download/"
      names <- paste("Origin_and_Destination_Survey_DB1BMarket", years, sep="_")
      info <- t(sapply(names, function(x) file.exists(paste(x, c("zip", "csv"), sep="."))))
      to.download <- paste(baseurl, names, ".zip", sep="")[!apply(info, 1, any)]
      if (length(to.download) > 0){
          message("starting download...")
          sapply(to.download,
                 function(x) download.file(x, rev(strsplit(x, "/")[[1]])[1]))}

      to.unzip <- paste(names,  "zip", sep=".")[!info[, 2]]
      if (length(to.unzip > 0)){
          message("starting to unzip...")
          sapply(to.unzip, unzip)}
      paste(names, "csv", sep=".")}

countWords.split <- function(x, s=":"){
    ## Faster on my machine than grep for some reanon
    sapply(strsplit(as.character(x), s), length)}

countWords.grep <- function(x){
    sapply(gregexpr("\\W+", x), length)+1}

fname <- dl.dta(2013.1)
cols <- rep("NULL", 41)
## Columns to keep: 9 is Origin, 18 is Dest, 24 is groups of airports in travel
## 30 is RPcarrier (reporting carrier).  
## For more columns: 35 is market fare and 36 is distance.
cols[9] <- cols[18] <- cols[24] <- cols[30] <- NA
d <- data.table(read.csv(file=fname,  colClasses=cols))
d[, Market := paste(Origin, Dest, sep=":")]
## should probably
d[, Stops := -2 + countWords.split(AirportGroup)]
d[, Carrier := RPCarrier]
d[, c("RPCarrier", "Origin", "Dest", "AirportGroup") := NULL]


推荐答案

@ Roland的答案将适用于某些功能最好),但不是一般。不幸的是,您不能将分割 - 应用 - 组合策略应用于数据,就像执行任务一样,但如果您使数据更大,您可以。让我们从一个更简单的例子开始:

@Roland's answer will work for some functions (and when it does it will be best) but not in general. Unfortunately you can't apply the split-apply-combine strategy to the data as is to do the task, but you can if you make the data larger. Let's start with a simpler example:

dt = data.table(a = c(1,1,2,2,3,3), b = c(1:6), key = 'a')

# now let's extend this table the following way
# take the unique a's and construct all the combinations excluding one element
combinations = dt[, combn(unique(a), 2)]

# now combine this into a data.table with the excluded element as the index
# and merge it back into the original data.table
extension = rbindlist(apply(combinations, 2,
                  function(x) data.table(a = x, index = setdiff(c(1,2,3), x))))
setkey(extension, a)

dt.extended = extension[dt, allow.cartesian = TRUE]
dt.extended[order(index)]
#    a index b
# 1: 2     1 3
# 2: 2     1 4
# 3: 3     1 5
# 4: 3     1 6
# 5: 1     2 1
# 6: 1     2 2
# 7: 3     2 5
# 8: 3     2 6
# 9: 1     3 1
#10: 1     3 2
#11: 2     3 3
#12: 2     3 4

# Now we have everything we need:
dt.extended[, mean(b), by = list(a = index)]
#   a  V1
#1: 3 2.5
#2: 2 3.5
#3: 1 4.5

返回原始数据(并做一些操作略有不同, ):

Going back to original data (and doing some operations slightly differently, to simplify expressions):

extension = d[, {Carrier.uniq = unique(Carrier);
                 .SD[, rbindlist(combn(Carrier.uniq, length(Carrier.uniq)-1,
                          function(x) data.table(Carrier = x,
                                   index = setdiff(Carrier.uniq, x)),
                          simplify = FALSE))]}, by = Market]
setkey(extension, Market, Carrier)

extension[d, allow.cartesian = TRUE][, mean(Stops), by = list(Market, Carrier = index)]
#    Market   Carrier       V1
#1: IAH:SNA Southwest 1.000000
#2: IAH:SNA     Delta 3.000000
#3: MSP:CLE   JetBlue 2.000000
#4: MSP:CLE Southwest 1.500000
#5: MSP:CLE  American 1.666667

这篇关于R:子集上的数据表,不包括值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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