获取Oracle Subquery中排序后的第一行 [英] Get the top row after order by in Oracle Subquery

问题描述

我有一个表学生（id，姓名，部门，年龄，分数）。我想找到最年轻的学生（在最年轻的学生中）每个部门的得分。在SQL Server中，我可以使用以下SQL。

I have a table student(id, name, department, age, score). I want to find the youngest student who has the highest(among the youngest students) score of each department. In SQL Server, I can use following SQL.

select * from student s1 
where s1.id in 
(select s2.id from student s2 
where s2.department = s1.department order by age asc, score desc top 1).

但是，在Oracle中，不能在子查询中使用order by子句，并且没有limit / top喜欢关键字。我必须加入学生表与自己两次查询结果。在oracle中，我使用以下SQL。

However, in Oracle, you cannot use the order by clause in subquery and there is no limit/top like keyword. I have to join the student table with itself two times to query the result. In oracle, I use following SQL.

select s1.* from student s1, 
(select s2.department, s2.age, max(s2.score) as max_score from student s2, 
(select s3.department, min(s3.age) as min_age from student s3 group by s3.department) tmp1 where 
s2.department = tmp1.department and s2.age = tmp1.min_age group by s2.department, s2.age) tmp2 
where s1.department =tmp2.department and s1.age = tmp2.age and s1.score=tmp2.max_score

任何人都有任何想法来简化上述SQL for oracle。

Does anyone have any idea to simplify the above SQL for oracle.

推荐答案

试试这个

select * from
  (SELECT id, name, department, age, score,
  ROW_NUMBER() OVER (partition by department order by age desc, score asc) srlno 
  FROM student) 
where srlno = 1;

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