将篮子转换为单一 [英] Convert basket to single

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本文介绍了将篮子转换为单一的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我目前有一个以篮子格式设置的表格,因此不规则的数据量与表格的每一行相关联。如:

  01,item1,item2,item3 
02,item1,item2,
03, item1,item2,item3,item4
04,item1

但我需要更改到规范化的事务格式,每行只有一个项目。如:

  01,item1 
01,item2
01,item3
02, item1
02,item2
03,item1

... 。是否有一个简单的自动或程序化的方式来做到这一点?数据目前在MySQL数据库中,我可以导出各种文件类型,我还可以访问RStudio和Microsoft Excel尝试这样做。我可以找到RStudio的所有事务资源假设数据已经是第二种格式,这是我想得到的。

解决方案

我假设我理解你的数据集看起来一旦你读它到R,即,它将是一个矩形数据框,其中NA的填充,使行的长度相同。所以这应该解决问题:

 #创建你的数据集(这一步不适合你)
row1 = c (01,item1,item2,item3,NA)
row2 = c(02,item1,item2,NA,NA)
row3 = c (03,item1,item2,item3,item4)
row4 = c(04,item1,NA,NA,NA)
$ b b Data = rbind(row1,row2,row3,row4)

#现在做重构(这一步适合你)
col1 = NULL
col2 = NULL

for(i in 1:nrow(Data)){
col1 = c(col1,rep(Data [i],ncol(Data)-1))
col2 = c col2,Data [i,-1])$ ​​b $ b}

NewData = cbind(col1,col2)[!is.na(col2),]



所以,你得到的是以下

 >数据
[,1] [,2] [,3] [,4] [,5]
row101item1item2item3NA
row202 item1item2NA NA
row303item1item2item3item4
row404item1NA NA NA
>
> NewData
col1 col2
[1,]01item1
[2,]01item2
[3,]01item3 b $ b [4,]02item1
[5,]02item2
[6, 03item2
[8,]03item3
[9,]03item4
[10,]04item1

希望有帮助。


I currently have a table set up in a basket format so that an irregular amount of data is associated with each row of the table. Such as:

01,item1,item2,item3
02,item1,item2,
03,item1,item2,item3,item4
04,item1

However, I need to change it to a normalized transactional format with only one item on each row. Such as:

01,item1
01,item2
01,item3
02,item1
02,item2
03,item1

...and so on. Is there an easy automated or programmatic way to do this? The data is currently in a MySQL database that I can export in a variety of file types, and I also have access to RStudio, and Microsoft Excel to try to do this. All the transactional resources I could find for RStudio assume that the data was already in the second format, which is what I'm trying to get to.

解决方案

I am assuming I understand the way your data set will look once you read it into R, i.e., it will be a rectangular data frame where NA's are filled in to make the rows the same length. So this should solve the problem:

#Create your dataset (this step is not for you)
row1 = c("01","item1","item2","item3",NA)
row2 = c("02","item1","item2",NA,NA)
row3 = c("03","item1","item2","item3","item4")
row4 = c("04","item1",NA,NA,NA)

Data = rbind(row1,row2,row3,row4)

#Now do the reconstruction (this step is for you)
col1 = NULL
col2 = NULL

for(i in 1:nrow(Data)){
    col1 = c(col1,rep(Data[i],ncol(Data)-1))
    col2 = c(col2,Data[i,-1])
}

NewData = cbind(col1,col2)[!is.na(col2),]

So, what you get is the following

> Data
     [,1] [,2]    [,3]    [,4]    [,5]   
row1 "01" "item1" "item2" "item3" NA     
row2 "02" "item1" "item2" NA      NA     
row3 "03" "item1" "item2" "item3" "item4"
row4 "04" "item1" NA      NA      NA     
> 
> NewData
      col1 col2   
 [1,] "01" "item1"
 [2,] "01" "item2"
 [3,] "01" "item3"
 [4,] "02" "item1"
 [5,] "02" "item2"
 [6,] "03" "item1"
 [7,] "03" "item2"
 [8,] "03" "item3"
 [9,] "03" "item4"
[10,] "04" "item1"

So hopefully that helps.

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