PHP功能问题 [英] PHP function issue

问题描述

尝试生成基于parent->子结构的db驱动菜单。所有根菜单项的父列值为0.连续地追踪以下错误

 未定义的偏移：0,1,2 （$ id，$ parent，$ name）= $ results; 
 
线上的未定义索引array_key_exists（）期望正好2个参数，1行上给出if（！array_key_exists（$ tree [$ parent] ['children'] [$ id]））{
 
警告：array_key_exists（）期望正好2个参数，1行上给出if（！array_key_exists（$ tree [$ parent] ['children'] [$ id]））{
  
 
 
 
  PHP CODE  
 <？php 
 
 function generateMenu（$ parent，$ level，$ menu，$ utype）{
 global $ db; 
 $ tree = array（）; 
 $ stmt = $ db-> prepare（select id，parent，name FROM navigation WHERE menu =？AND user_type =？）或die（$ db-> error）; 
 $ stmt-> bind_param（ii，$ menu，$ utype）或die（$ stmt-> error）; 
 $ stmt-> execute（）或die（$ stmt-> error）; 
 $ stmt-> store_result（）; 
 $ meta = $ stmt-> result_metadata（）; 
 $ bindResult = array（）; 
 while（$ columnName = $ meta-> fetch_field（））{
 $ bindResult [] =& $ results [$ columnName-> name]; 
} 
 call_user_func_array（array（$ stmt，'bind_result'），$ bindResult）; 
 while（$ stmt-> fetch（））{
 list（$ id，$ parent，$ name）= $ results; 
 $ tree [$ id] = array（'name'=> $ name，'children'=> array（），'parent'=> $ parent）; 
 if（！array_key_exists（$ id，$ tree [$ parent] ['children']））{
 $ tree [$ parent] ['children'] [$ id] = $ id; 
} 
} 
 $ stmt-> close（）; 
 print_r（$ tree）; 
} 
 
？> 
  
 和数据库结构 
 
 
 
 > 
 
 
 
 用于测试目的 
 
 
 
 
 
尝试 die（print_r（$ results））; 正好在之后，而
（$ stmt-> fetch（））{。获取我的db表的第一行为 Array（
 [id] => 1 [parent] => 0 [name] => Sual）1  
 
 
 
尝试 while（$ results = $ stmt-> fetch（））{而不是 while（$ stmt-> fetch（））{。再次遇到以下错误
 
 
 
线上的未定义索引array_key_exists（）期望正好2个参数，1行上给出if（！array_key_exists（$ tree [$ parent] ] [$ id]））{
 
 
 
警告：array_key_exists（）只需要2个参数，  if（！array_key_exists（$ id，$ tree [$ parent] [child]] [$ id]）
 
 'child']））{而不是 if（！array_key_exists（$ tree [$ parent] ['children'] [$ id]））{。再次遇到以下错误
 
 
 
未定义的偏移：0,1,2在线列表（$ id，$ parent，$ name）= $ results; 
  
 
 
 
 
无法弄清楚，出了什么问题。请帮助解决这个问题
解决方案
 
 
 //尝试回显列表值
 / /你的语法错误
 array_key_exists（$ yourKey，$ yourSearchArray）; 
 
 
Trying to generate db driven menu which based on parent->child structure. All root menu items' parent column values are 0. Geeting following errors continuously
Undefined offset: 0,1,2 on line list($id, $parent, $name) = $results; 

 Undefined index on line  array_key_exists() expects exactly 2 parameters, 1 given on line   if (!array_key_exists($tree[$parent]['children'][$id])) {

Warning: array_key_exists() expects exactly 2 parameters, 1 given on line   if (!array_key_exists($tree[$parent]['children'][$id])) {
PHP CODE
<?php

function generateMenu($parent, $level, $menu, $utype) {
    global $db;
    $tree = array();
    $stmt = $db->prepare("select id, parent, name FROM navigation WHERE menu=? AND user_type=?") or die($db->error);
    $stmt->bind_param("ii", $menu, $utype) or die($stmt->error);
    $stmt->execute() or die($stmt->error);
    $stmt->store_result();
    $meta = $stmt->result_metadata();
    $bindResult = array();
    while ($columnName = $meta->fetch_field()) {
        $bindResult[] = &$results[$columnName->name];
    }
    call_user_func_array(array($stmt, 'bind_result'), $bindResult);
    while ($stmt->fetch()) {
        list($id, $parent, $name) = $results;
        $tree[$id] = array('name' => $name, 'children' => array(), 'parent' => $parent);
        if (!array_key_exists($id, $tree[$parent]['children'])) {
            $tree[$parent]['children'][$id] = $id;
        }
    }
    $stmt->close();
    print_r($tree);
}

?>
And DB structure



For testing purposes


Tried   die(print_r($results)); right after  while
($stmt->fetch()) {. Getting first row of my db table as Array (
[id] => 1 [parent] => 0 [name] => Sual ) 1.
Tried   while ($results=$stmt->fetch()) { instead of while ($stmt->fetch()) {. Got following errors again 

Undefined index on line  array_key_exists() expects exactly 2 parameters, 1 given on line   if (!array_key_exists($tree[$parent]['children'][$id])) {

Warning: array_key_exists() expects exactly 2 parameters, 1 given on line   if (!array_key_exists($tree[$parent]['children'][$id])) {
Tried   if (!array_key_exists($id, $tree[$parent]['children'])) { instead of if (!array_key_exists($tree[$parent]['children'][$id])) {. Got following errors again 

Undefined offset: 0,1,2 on line list($id, $parent, $name) = $results; 


Can't figure out, what's wrong. Please help to fix that problem
解决方案
//try echoing the list values
//Your syntax is wrong
array_key_exists($yourKey, $yourSearchArray);


                        
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