如何以编程方式形成可观察的集合并将其绑定到数据网格 [英] How to programmatically form an observable collection and bind it to a datagrid

问题描述

我有一个问题，我会分两步：

I have a problem which i'd divide in two steps:

问题1。

形成一个可观察的字符串集合，并将其绑定到datagrid

Form an observable collection of strings and bind it to a datagrid

ObservableCollection<string[]> octest = new ObservableCollection<string[]>();
var el = new string[6] {"1","2","3", "4", "5", "6" };
octest.Add(el);
octest.Add(el);
octest.Add(el);
dtgResults.ItemsSource = octest;

问题是绑定结果如下图：

the problem is that the binding results in the image below:

问题2

相同但现在有一个字符串数组，但是混合元素（例如3个字符串和3个双精度）

The same but now with an array of strings but with mixed elements (e.g. 3 strings and 3 doubles)

谢谢

- 编辑CBreeze

--EDIT-- for CBreeze

我已经做到了： p>

I have done that:

  ObservableCollection<TestModel> t = new ObservableCollection<TestModel>();
  var t1 = new TestModel();
  t.Add(t1);
  t.Add(t1);
  t.Add(t1);
  dtgResults.ItemsSource = t;
 }
}

public class TestModel
{
  public TestModel()
  {
    TestDouble1 = new string[3];
    TestDouble1[0] = "A";
    TestDouble1[1] = "B";
    TestDouble1[2] = "C";
  }
  public string[] TestDouble1 { get; set; }
}

，结果是：

推荐答案

从

以编程方式添加列&行到WPF Datagrid

你可以这样做：

string[] columnLabels = new string[] { "Column 0", "Column 1", "Column 2", "Column 3", "Column 4", "Column 5" };

foreach (string label in columnLabels)
{
 DataGridTextColumn column = new DataGridTextColumn();
 column.Header = label;
 column.Binding = new Binding(label.Replace(' ', '_'));

 dtgResults.Columns.Add(column);
}

int[] ivalues = new int[] { 0, 1, 2, 3 };
string[] svalues = new string[] { "A", "B", "C", "D" };

dynamic row = new ExpandoObject();

for (int i = 0; i < 6; i++)
{

 switch (i)
 {
  case 0:
  case 1:
  case 2:
   string str = columnLabels[i].Replace(' ', '_');
   ((IDictionary<String, Object>)row)[str] = ivalues[i];
   break;

   case 3:
   case 4:
   case 5:
    string str2 = columnLabels[i].Replace(' ', '_');
    ((IDictionary<String, Object>)row)[str2] = svalues[i - 3];
    break;

 }
}

dtgResults.Items.Add(row);

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