在R中合并多个csv文件 [英] Merging multiple csv files in R
本文介绍了在R中合并多个csv文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
LatLonValue1Value2 ...价值100
Lat
和 Lon
列对于所有csv文件是相同的。合并两个文件很容易
merge(data.frame1,data.frame2,by = c('Lat','Lon' ))
但是,我尝试了以下没有工作的代码:
file_list< - list.files(〜/ source)
list_of_files< - lapply(file_list,read.csv)
m1< ; - merge_all(list_of_files,by = c(Lat,Lon),all = TRUE)
发出错误
merge.data.frame(dfs [[1]]中的错误,Recall(dfs [ - 1]),all = TRUE,sort = FALSE,
正式参数all由多个实际参数匹配
任何人都可以在这方面帮助我。
解决方案
您可以使用 减少
和合并
:
m1< - 减少(function旧,新){merge(old,new,by = c ('Lat','Lon'))},list_of_files)
I have around 100 csv files with common headers, which i want to merge. The headers are "Lat", "Long" and "value". I am trying to merge all the csv files such that the output would be
"Lat" "Lon" "Value1" "Value2"..."Value 100"
Lat
and Lon
columns are identical for all of the csv files. Merging two files is easy
merge(data.frame1, data.frame2, by=c('Lat','Lon'))
However, I tried the following code which didnt work:
file_list <- list.files(~/source)
list_of_files <- lapply(file_list, read.csv)
m1 <- merge_all(list_of_files, by=c("Lat","Lon"), all=TRUE)
which throws the error
Error in merge.data.frame(dfs[[1]], Recall(dfs[-1]), all = TRUE, sort = FALSE, :
formal argument "all" matched by multiple actual arguments.
Can anyone help me in this regard.
解决方案
You can use Reduce
and the plain merge
:
m1 <- Reduce(function(old, new) { merge(old, new, by=c('Lat','Lon')) }, list_of_files)
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