在WPF中过滤DataGrid [英] Filter a DataGrid in WPF

问题描述

  dataGrid1.Items.Add（model）; 
  

模型成为数据库中的数据。它有一个 Id（int）， Name（string）和 Text（string）

在我的datagrid中，我只显示模型的名称。当我在文本框中输入内容时，现在可以如何过滤datagrid？

我在这个页面上： http://msdn.microsoft.com/en-us/library/vstudio/ff407126（v = vs .100）.aspx ，但我不明白那里的代码，我无法解释我应该如何处理我的问题。

解决方案

有多种方式来过滤集合

我们建议这是您的项目类

  public class Model 
 {
 public string Name 
 {
 get; 
设置; 
} 
} 
  

，您的收藏看起来像

  var ObColl = new ObservableCollection< Model>（）; 
 
 ObColl.Add（new Model（）{Name =John}）; 
 ObColl.Add（new Model（）{Name =Karl}）; 
 ObColl.Add（new Model（）{Name =Max}）; 
 ObColl.Add（new Model（）{Name =Mary}）; 
  

方式1（谓词）：

  public MainWindow（）
 {
 InitializeComponent（）; 
 
 //收集您的ObservableCollection 
 var _itemSourceList = new CollectionViewSource（）{Source = ObColl}; 
 
 // ICollectionView View / UI部分
 ICollectionView Itemlist = _itemSourceList.View; 
 
 //您的Filter 
 var yourCostumFilter = new Predicate< object>（item =>（（Model）item）.Name.Contains（Max））; 
 
 //现在我们添加过滤器
 Itemlist.Filter = yourCostumFilter; 
 
 dataGrid1.ItemsSource = Itemlist; 
} 
  

Way 2（FilterEventHandler）：

  public MainWindow（）
 {
 InitializeComponent（）; 
 
 //收集你的过滤器
 var _itemSourceList = new CollectionViewSource（）{Source = ObColl}; 
 
 //现在我们添加我们的Filter 
 _itemSourceList.Filter + = new FilterEventHandler（yourFilter）; 
 
 // ICollectionView View / UI部分
 ICollectionView Itemlist = _itemSourceList.View; 
 
 dataGrid1.ItemsSource = Itemlist; 
} 
 
 private void yourFilter（object sender，FilterEventArgs e）
 {
 var obj = e.Item as Model; 
 if（obj！= null）
 {
 if（obj.Name.Contains（Max））
 e.Accepted = true; 
 else 
 e.Accepted = false; 
} 
} 
  

扩展信息到路1

如果需要多个条件或一些复杂的过滤器，您可以向Predicat添加一个方法

  / /你的过滤器
 var yourComplexFilter = new Predicate< object>（ComplexFilter）; 
 
 private bool ComplexFilter（object obj）
 {
 //您的逻辑
} 
  

I load a lists of objects in a datagrid with this:

dataGrid1.Items.Add(model);

The model become data from a database. It has a Id(int), Name(string) and Text(string)

In my datagrid I show only the Name of the model. How can I filter the datagrid now, when I enter something in a textbox?

I was at this page: http://msdn.microsoft.com/en-us/library/vstudio/ff407126(v=vs.100).aspx but I don't understand the code from there and I can not explain how I should transpose that for my problem.

解决方案

there are multiple way's to filter Collection

let's suggesting this is your Item Class

public class Model
{
    public string Name
    {
        get;
        set;
    }
}

and your collection looks like

       var ObColl = new ObservableCollection<Model>();

        ObColl.Add(new Model() { Name = "John" });
        ObColl.Add(new Model() { Name = "Karl" });
        ObColl.Add(new Model() { Name = "Max" });
        ObColl.Add(new Model() { Name = "Mary" });

Way 1 (Predicate):

    public MainWindow()
    {
        InitializeComponent();

        // Collection which will take your ObservableCollection
        var _itemSourceList = new CollectionViewSource() { Source = ObColl };

        // ICollectionView the View/UI part 
        ICollectionView Itemlist = _itemSourceList.View;

        // your Filter
        var yourCostumFilter= new Predicate<object>(item => ((Model)item).Name.Contains("Max"));

        //now we add our Filter
        Itemlist.Filter = yourCostumFilter;

        dataGrid1.ItemsSource = Itemlist;
    }

Way 2 (FilterEventHandler):

    public MainWindow()
    {
        InitializeComponent();

        // Collection which will take your Filter
        var _itemSourceList = new CollectionViewSource() { Source = ObColl };

       //now we add our Filter
       _itemSourceList.Filter += new FilterEventHandler(yourFilter);

        // ICollectionView the View/UI part 
        ICollectionView Itemlist = _itemSourceList.View;

        dataGrid1.ItemsSource = Itemlist;
    }

    private void yourFilter(object sender, FilterEventArgs e)
    {
        var obj = e.Item as Model;
        if (obj != null)
        {
            if (obj.Name.Contains("Max"))
                e.Accepted = true;
            else
                e.Accepted = false;
        }
    }

extended Information to Way 1

if need multiple conditions or some complex Filter you can add a method to your Predicat

    // your Filter
    var yourComplexFilter= new Predicate<object>(ComplexFilter);

    private bool ComplexFilter(object obj)
    {
        //your logic
    }

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