Linq Datagrid从xml文件绑定 [英] Linq Datagrid binding from xml file
问题描述
< Department Name ='D1'TotalCapacity ='5' >
< Class Name ='c1'Capacity ='3'>< / Class>
< Class Name ='c2'Capacity ='2'>< / Class>
< / Department>
< Department Name ='D2'TotalCapacity ='10'>
< Class Name ='c1'Capacity ='5'>< / Class>
< Class Name ='c3'Capacity ='5'>< / Class>
< / Department>
现在,根据这个xml,我希望数据网格显示为:
部门名称 TotalCapacity c1 c2 c3 / p>
D1 5 3 2 -
D2 10 5 - 5
我很好奇,没有做过你以前想做的,所以我想到我会给它一个刺关于此主题的此MSDN文章,我想出了这个:
< Grid>
< Grid.Resources>
< XmlDataProvider x:Key =DepartmentDataXPath =部门/部门>
< x:XData>
< Departments xmlns =>
< Department Name ='D1'TotalCapacity ='5'>
< Class Name ='c1'Capacity ='3'/>
< Class Name ='c2'Capacity ='2'/>
< / Department>
< Department Name ='D2'TotalCapacity ='10'>
< Class Name ='c1'Capacity ='5'/>
< Class Name ='c3'Capacity ='5'/>
< / Department>
< / Departments>
< / x:XData>
< / XmlDataProvider>
< /Grid.Resources>
< DataGrid ItemsSource ={Binding Source = {StaticResource DepartmentData}}AutoGenerateColumns =False>
< DataGrid.Columns>
< DataGridTextColumn Header =部门名称Binding ={Binding XPath = @ Name}/>
< DataGridTextColumn Header =Total CapacityBinding ={Binding XPath = @ TotalCapacity}/>
< DataGridTextColumn标题=c1>
< DataGridTextColumn.Binding>
< Binding XPath =Class [@ Name ='c1'] / @ Capacity/>
< /DataGridTextColumn.Binding>
< / DataGridTextColumn>
< DataGridTextColumn标题=c2>
< DataGridTextColumn.Binding>
< Binding XPath =Class [@ Name ='c2'] / @ Capacity/>
< /DataGridTextColumn.Binding>
< / DataGridTextColumn>
< DataGridTextColumn Header =c3>
< DataGridTextColumn.Binding>
< Binding XPath =Class [@ Name ='c3'] / @ Capacity/>
< /DataGridTextColumn.Binding>
< / DataGridTextColumn>
< /DataGrid.Columns>
< / DataGrid>
< / Grid>
结果:
祝你好运!
编辑:
我刚刚意识到您要求列动态添加 - 我不知道有一个简单的方法来做,因为您的XML不是以格式显示在格式的表格(我必须使用一些XPath魔术将XML转换为平面格式)结构化。希望这会让你走上正确的道路。
I am developing an application in wpf in which i have one datagrid. i want the columns of datagrid to be added dynamically from xml.
<Department Name='D1' TotalCapacity='5'>
<Class Name='c1' Capacity='3'></Class>
<Class Name='c2' Capacity='2'></Class>
</Department>
<Department Name='D2' TotalCapacity='10'>
<Class Name='c1' Capacity='5'></Class>
<Class Name='c3' Capacity='5'></Class>
</Department>
Now, based on this xml i want the datagrid to be displayed as :
DepartmentName TotalCapacity c1 c2 c3
D1 5 3 2 -
D2 10 5 - 5
I was curious, and haven't done what you're trying to do before, so I figured I'd give it a stab. Going through this this MSDN article on the subject, I came up with this:
<Grid>
<Grid.Resources>
<XmlDataProvider x:Key="DepartmentData" XPath="Departments/Department">
<x:XData>
<Departments xmlns="">
<Department Name='D1' TotalCapacity='5'>
<Class Name='c1' Capacity='3'/>
<Class Name='c2' Capacity='2'/>
</Department>
<Department Name='D2' TotalCapacity='10'>
<Class Name='c1' Capacity='5'/>
<Class Name='c3' Capacity='5'/>
</Department>
</Departments>
</x:XData>
</XmlDataProvider>
</Grid.Resources>
<DataGrid ItemsSource="{Binding Source={StaticResource DepartmentData}}" AutoGenerateColumns="False">
<DataGrid.Columns>
<DataGridTextColumn Header="Department Name" Binding="{Binding XPath=@Name}"/>
<DataGridTextColumn Header="Total Capacity" Binding="{Binding XPath=@TotalCapacity}"/>
<DataGridTextColumn Header="c1">
<DataGridTextColumn.Binding>
<Binding XPath="Class[@Name='c1']/@Capacity"/>
</DataGridTextColumn.Binding>
</DataGridTextColumn>
<DataGridTextColumn Header="c2">
<DataGridTextColumn.Binding>
<Binding XPath="Class[@Name='c2']/@Capacity"/>
</DataGridTextColumn.Binding>
</DataGridTextColumn>
<DataGridTextColumn Header="c3">
<DataGridTextColumn.Binding>
<Binding XPath="Class[@Name='c3']/@Capacity"/>
</DataGridTextColumn.Binding>
</DataGridTextColumn>
</DataGrid.Columns>
</DataGrid>
</Grid>
The result:
Good luck!
Edit:
I just realized you asked for the columns to be dynamically added - I'm not sure there's a straightforward way to do that, seeing as your XML isn't structured in a format that lends itself to tabular display out of the box (I had to use some XPath magic to transform your XML to a flat format). Hopefully this will get you on the right path though.
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