超链接在DataGridView [英] HyperLinks In DataGridView

问题描述

我正在C＃应用程序上工作，就像一个小型的搜索引擎。用户将输入一个单词，程序将返回包含该单词的文件。

我有一个文件路径数组（作为字符串），我想显示这些路径作为 DataGridView 中的链接，以便用户单击文件名时将打开该文件。

注意：我正在使用C＃Winforms，而不是ASP.net

解决方案

我想我有我的问题的答案
我添加了一个DataGridViewLinkColumn到DataGridView
现在下一步将数据填充到datagridview
，文件名将显示为链接：

  private void button1_Click（object sender，EventArgs e）
 {
 string [] SS = new string [3]; 
 SS [0] =C：\\test1.txt; 
 SS [1] =C：\\test2.txt; （int i = 0; i  {
 dataGridView1.Rows.Add（SS [i]）; 
 
} 
 dataGridView1.Refresh（）; 
} 
  

最后一步：
现在我要打开文件用户点击它
我将使用CellContentClick事件，此代码将实现：

  private void dataGridView1_CellContentClick （object sender，DataGridViewCellEventArgs e）
 {
 string filepath =（string）dataGridView1.Rows [e.RowIndex] .Cells [0] .Value; 
 System.Diagnostics.Process.Start（filepath）; 
} 
  

I am working on C# application which is like a small search engine. The user will enter a word and the program will return the files that contains this word.

I have an array of file paths (as strings) and I want to show these paths as links in a DataGridView, so that when the user clicks the file name the file will be opened.

Note: I am working on C# Winforms, not ASP.net

解决方案

I think I have The Answer of my question I added a DataGridViewLinkColumn to the DataGridView now the next step will fill the Data into the datagridview and the File names will appear like links:

private void button1_Click(object sender, EventArgs e)
    {
        string[] SS = new string[3];
        SS[0] = "C:\\test1.txt";
        SS[1] = "C:\\test2.txt";
        for (int i = 0; i < SS.Length; i++)
        {
            dataGridView1.Rows.Add(SS[i]);
        }
        dataGridView1.Refresh();
    }

The Last step : now I want to open the file when the user click it I will use the "CellContentClick" event and this code will achieve it:

private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
    {
        string filepath= (string)dataGridView1.Rows[e.RowIndex].Cells[0].Value;
        System.Diagnostics.Process.Start(filepath);
    }

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