AJAX语法错误：JSON.parse：意外的字符 [英] AJAX SyntaxError: JSON.parse: unexpected character
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问题描述
我一直在试图找出问题，这几天。由于我的数据被发送和检索，但它并没有张贴到我的分区。为什么？我做了一个测试，发现我一个SyntaxError意想不到的角色。而且我可以找到它。可我心里很不舒服。
有人可以期待通过这一点，并告诉任何错误，我请。
＆LT;脚本＆GT;
$（文件）。就绪（函数（）{
$（＃形式mycommentform）。递交（函数（）{
VAR streamidcontent = $（本）。儿童（＃streamidcontent）VAL（）。
。VAR内容= $（本）。儿童（＃内容）VAL（）;
$阿贾克斯（{
键入：POST，
网址：comment_add.php
缓存：假的，
数据类型：JSON，
数据：{streamidcontent：streamidcontent，内容：内容}，
成功：功能（数据）{
$（＃containerid）HTML（'＆LT; DIV CLASS =stream_comment_holderID =comment_holder _'+数据['comment_streamitem'] +'＆GT; \
＆LT; DIV ID =comment_list _'+数据['comment_streamitem'] +'＆GT; \
＆LT; DIV ID =TGY＆GT;＆LT; / DIV＆GT;＆LT; DIV CLASS =stream_commentID =评论_'+数据['COMMENT_ID'] +'的风格=的margin-top：0px;＆GT; \
＆LT;表格的宽度= 100％GT;＆LT; TR＆GT;＆LT; TD VALIGN =顶宽= 30PX＆GT;＆LT; / A＆GT;＆LT; TD VALIGN =顶部对齐=左＆GT; \
＆LT; A HREF =？/ profile.php用户名='+数据['用户名'] +'＆GT;'+数据['第一'] +'＆LT; / A＆GT; \
＆LT; DIV CLASS =commentholder＆GT;'+数据['第一'] +'＆LT; / DIV＆GT;＆LT; BR /＆GT; \
＆LT; DIV ID =commentactivitycontainer＆GT;＆LT; / DIV＆GT;＆LT; / DIV＆GT;＆LT; /表＆gt;＆LT; / DIV＆GT;＆LT; / DIV＆GT; \
＆LT; DIV CLASS =形与GT;＆LT;形式ID =mycommentform方法=POST级=form_statusinput＆GT; \
＆LT;输入类型=隐藏名称=streamidcontentID =streamidcontent值=+数据['comment_streamitem'] +'＆GT; \
＆LT;输入类型=文本名称=内容ID =内容占位符=说什么自动完成=关闭＆GT; \
＆LT;输入类型=提交ID =按钮值=频道＆GT;＆LT; /形式GT;＆LT; / DIV＆GT; \
＆LT; DIV CLASS =stream_comment_holder的风格=显示：;＆GT;＆LT; DIV CLASS =like_name＆GT;＆LT; B＆GT; \
＆LT; A HREF =？profile.php用户名='+数据['用户名'] +'＆gt;您像该＆lt; / A＆GT; \
＆LT; / B＆GT;＆LT; / DIV＆GT;＆LT; / DIV＆GT;'）;
警报（成功！）;
}，
错误：函数（XHR，ajaxOptions，thrownError）{
警报（xhr.statusText）;
警报（xhr.status）;
警报（thrownError）;
}
}）;
返回false
}）;
}）;
＆LT; / SCRIPT＆GT;
REPONSE
INSERT INTO streamdata_comments（comment_poster，comment_streamitem，comment_datetime，comment_content）VALUES (10,4090,UTC_TIMESTAMP(),'fff'){"comment_id":"2016","comment_streamitem":"4090","username":"hazy","id":"10","first":"Lucy","middle":"","last":"Botham"}
PHP页面
＆LT; PHP
在session_start（）;
要求包括/ rawfeeds_load.php;
如果（使用isset（$ _ POST ['streamidcontent']）及使用isset（$ _ POST ['内容']））{
rawfeeds_user_core :: add_comment（$ _ POST ['streamidcontent']，$ _ POST ['内容']）;
$ JSON =阵列（）;
$查询=选择COMMENT_ID，comment_datetime，comment_streamitem，comment_poster从streamdata_comments WHERE comment_poster ='。$ _ SESSION ['身份证'。'和comment_streamitem ='。$ _ POST ['streamidcontent'。'ORDER BY comment_datetime降序;
$ CHECK1 = mysqli_query（$ mysqli的，$检查）;
$ resultArr = mysqli_fetch_array（$ CHECK1）;
$ JSON ['COMMENT_ID'] = $ resultArr ['COMMENT_ID'];
$ JSON ['comment_streamitem'] = $ resultArr ['comment_streamitem'];
mysqli_free_result（$ CHECK1）;
$查询=SELECT * FROM用户WHERE ID =$ _ SESSION ['身份证']。;
$ CHECK1 = mysqli_query（$ mysqli的，$检查）;
$ resultArr = mysqli_fetch_array（$ CHECK1）;
$ JSON [用户名] = $ resultArr [用户名];
$ JSON ['身份证'] = $ resultArr ['身份证'];
$ JSON ['第一'] = $ resultArr ['第一'];
$ JSON ['中间'] = $ resultArr ['中间'];
$ JSON ['最后'] = $ resultArr ['最后'];
mysqli_free_result（$ CHECK1）;
回声json_en code（$ JSON）;
}
？＆GT;
解决方案
如上所述@thomas。我是呼应了SQL查询伸到我的功能。我删除了这一点，它现在可以正常使用。
I've been trying to find out the issue with this for days. As my data is being sent and retrieved, yet it doesn't post into my div.. Why? I did a test and found that I a SyntaxERROR unexpected character.. And can I find it.. Can I heck.
Can someone look through this and tell me of any mistakes please.
<script>
$(document).ready(function(){
$("form#mycommentform").submit(function() {
var streamidcontent = $(this).children("#streamidcontent").val();
var contents = $(this).children("#contents").val();
$.ajax({
type: "POST",
url: "comment_add.php",
cache: false,
dataType: "json",
data: { streamidcontent: streamidcontent, contents: contents },
success: function(data){
$("#containerid").html('<div class="stream_comment_holder" id="comment_holder_'+data['comment_streamitem']+'">\
<div id="comment_list_'+data['comment_streamitem']+'">\
<div id="tgy"></div><div class="stream_comment" id="comment_'+data['comment_id']+'" style="margin-top:0px;">\
<table width=100%><tr><td valign=top width=30px></a><td valign=top align=left>\
<a href="/profile.php?username='+data['username']+'">'+data['first']+'</a>\
<div class="commentholder">'+data['first']+'</div><br/>\
<div id="commentactivitycontainer"></div></div></table></div></div>\
<div class="form"><form id="mycommentform" method="POST" class="form_statusinput">\
<input type="hidden" name="streamidcontent" id="streamidcontent" value="'+data['comment_streamitem']+'">\
<input type="text" name="contents" id="contents" placeholder="Say something" autocomplete="off">\
<input type="submit" id="button" value="Feed"></form></div>\
<div class="stream_comment_holder" style="display:;"><div class="like_name"><b>\
<a href="profile.php?username='+data['username']+'">You Like This</a>\
</b></div></div>');
alert("SUCCESS!!!");
},
error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.statusText);
alert(xhr.status);
alert(thrownError);
}
});
return false
});
});
</script>
REPONSE
INSERT INTO streamdata_comments(comment_poster, comment_streamitem, comment_datetime, comment_content) VALUES (10,4090,UTC_TIMESTAMP(),'fff'){"comment_id":"2016","comment_streamitem":"4090","username":"hazy","id":"10","first":"Lucy","middle":"","last":"Botham"}
PHP PAGE
<?php
session_start();
require"include/rawfeeds_load.php";
if(isset($_POST['streamidcontent'])&isset($_POST['contents'])){
rawfeeds_user_core::add_comment($_POST['streamidcontent'],$_POST['contents']);
$json = array();
$check = "SELECT comment_id, comment_datetime, comment_streamitem, comment_poster FROM streamdata_comments WHERE comment_poster='".$_SESSION['id']."' AND comment_streamitem='".$_POST['streamidcontent']."' ORDER BY comment_datetime DESC";
$check1 = mysqli_query($mysqli,$check);
$resultArr = mysqli_fetch_array($check1);
$json['comment_id'] = $resultArr['comment_id'];
$json['comment_streamitem'] = $resultArr['comment_streamitem'];
mysqli_free_result($check1);
$check = "SELECT * FROM users WHERE id=".$_SESSION['id']."";
$check1 = mysqli_query($mysqli,$check);
$resultArr = mysqli_fetch_array($check1);
$json['username'] = $resultArr['username'];
$json['id'] = $resultArr['id'];
$json['first'] = $resultArr['first'];
$json['middle'] = $resultArr['middle'];
$json['last'] = $resultArr['last'];
mysqli_free_result($check1);
echo json_encode($json);
}
?>
解决方案
As @thomas stated above. I was echoing the SQL query out into my function. I removed this and its now working perfectly.
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