从PHP日期获取周数（年） [英] Get week number (in the year) from a date PHP

问题描述

到目前为止，到目前为止，它应该是24，当它应该是42。 / p>

 <？php 
 $ ddate =2012-10-18; 
 $ duedt = explode（ - ，$ ddate）; 
 $ date = mktime（0，0，0，$ duedt [2]，$ duedt [1]，$ duedt [0]）; 
 $ week =（int）date（'W'，$ date）; 
 echoWeeknummer：。$ week; 
？> 
  

是错误的，数字颠倒的巧合吗？或者我几乎在那里？

解决方案

今天，使用PHP的 DateTime 对象更好：

 <？php 
 $ ddate =2012-10-18; 
 $ date = new DateTime（$ ddate）; 
 $ week = $ date->格式（W）; 
 echoWeeknummer：$ week; 
  

---

这是因为在 mktime （），它如下所示：

  mktime（小时，分，秒，月，日） ， 年）; 
  

因此，您的订单是错误的。

 <？php 
 $ ddate =2012-10-18; 
 $ duedt = explode（ - ，$ ddate）; 
 $ date = mktime（0，0，0，$ duedt [1]，$ duedt [2]，$ duedt [0]）; 
 $ week =（int）date（'W'，$ date）; 
 echoWeeknummer：。 $ week; 
？> 
  

I want to take a date and work out what week number is.

So far I have so far, it is returning 24 when it should be 42.

<?php
$ddate = "2012-10-18";
$duedt = explode("-",$ddate);
$date = mktime(0, 0, 0, $duedt[2], $duedt[1],$duedt[0]);
$week = (int)date('W', $date);
echo "Weeknummer: ".$week;
?>

is it wrong and a coincidence that the numbers are reversed? Or am I nearly there?

解决方案

Today, using PHP's DateTime objects is better:

<?php
$ddate = "2012-10-18";
$date = new DateTime($ddate);
$week = $date->format("W");
echo "Weeknummer: $week";

---

It's because in mktime(), it goes like this:

mktime(hour, minute, second, month, day, year);

Hence, your order is wrong.

<?php
$ddate = "2012-10-18";
$duedt = explode("-", $ddate);
$date  = mktime(0, 0, 0, $duedt[1], $duedt[2], $duedt[0]);
$week  = (int)date('W', $date);
echo "Weeknummer: " . $week;
?>

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