获取下一个有效日期 [英] Fetching next valid day

问题描述

我正在写一个java应用程序，我需要执行以下操作。

我必须避免两个星期（外部可配置），说TUESDAY和FRIDAY到做一些业务逻辑处理。我想找出下一个可用的日子。例如：如果今天是TUESDAY，我应该得到WEDNESDAY作为下一个可用或如果今天是THURSDAY，那么下一个可以是MONDAY。

有人可以指导我解决这个问题？这听起来很简单，但它真的是三脚架。

这是我迄今为止所做的一切。

 列表< String> exceptionDays = new ArrayList< String>（）; 
 exceptionDays.add（SUNDAY）; 
 exceptionDays.add（MONDAY）; 
 exceptionDays.add（FRIDAY）; 
 
日期date = new Date（）; 
 
日历calendar = Calendar.getInstance（）; 
 calendar.setTime（今）; 
 
 int dayOfWeek = calendar.get（Calendar.DAY_OF_WEEK）; 
 
 if（dayOfWeek == Calendar.FRIDAY）{
 calendar.add（Calendar.DATE，3）; 
}其他if（dayOfWeek == Calendar.SATURDAY）{
 calendar.add（Calendar.DATE，2）; 
} else {
 calendar.add（Calendar.DATE，1）; 
} 
 String strDateFormat =E; 
 SimpleDateFormat sdf = new SimpleDateFormat（strDateFormat）; 
 
 strDateFormat =EEEE; 
 sdf = new SimpleDateFormat（strDateFormat）; 
 
日期nextBusinessDay = calendar.getTime（）; 
 System.out.println（sdf.format（nextBusinessDay）.toUpperCase（））; 
 if（exceptionDays.contains（sdf.format（nextBusinessDay）.toUpperCase（）））{
 if（sdf.format（nextBusinessDay）.toUpperCase（）。equals（FRIDAY））{
 calendar.add（Calendar.DATE，3）; 
} else if（sdf.format（nextBusinessDay）.toUpperCase（）。equals（SATURDAY））{
 calendar.add（Calendar.DATE，2）; 
} else 
 calendar.add（Calendar.DATE，1）; 
 
 
 nextBusinessDay = calendar.getTime（）; 
} 
 DateFormat df = new SimpleDateFormat（dd-MMM-yy）; 
 String format = df.format（nextBusinessDay.getTime（））; 
 System.out.println（今天：+ df.format（今天））; 
 try {
 System.out.println（下一个工作日：+ df.parse（format））; 
 
 System.out.println（下一个工作日：+ df.format（nextBusinessDay））; 
  

如果看起来很笨拙，请忽略上述逻辑。

解决方案

简单使用日历

 列表<整数> avoidDays = new ArrayList< Integer>（）; 
 avoidDays.add（Calendar.MONDAY）; 
日历cal = Calendar.getInstance（）; 
 while（avoidDays.contains（cal.get（Calendar.DAY_OF_WEEK）））{cal.add（Calendar.DATE，1} 
 return cal; 
  / pre> 
I am writing one java application where i need to do the following.

I have to avoid two days of a week (externally configurable) say TUESDAY and FRIDAY to do some business logic processing. I want to find out the next available day. For Example : if today is TUESDAY, I should get WEDNESDAY as next available or if today is THURSDAY, then the next available should be MONDAY.

Could someone guide me solving this ? This sounds simple but its really trickey.

Here is what i did so far 
       List<String> exceptionDays = new ArrayList<String>();
  exceptionDays.add("SUNDAY");
  exceptionDays.add("MONDAY");
  exceptionDays.add("FRIDAY");

  Date today = new Date();

      Calendar calendar = Calendar.getInstance();
      calendar.setTime(today);

  int dayOfWeek = calendar.get(Calendar.DAY_OF_WEEK);

  if (dayOfWeek == Calendar.FRIDAY) {
      calendar.add(Calendar.DATE, 3);
  } else if (dayOfWeek == Calendar.SATURDAY) {
      calendar.add(Calendar.DATE, 2);
  } else {
      calendar.add(Calendar.DATE, 1);
  }
  String strDateFormat = "E";
  SimpleDateFormat sdf = new SimpleDateFormat(strDateFormat);

  strDateFormat = "EEEE";
  sdf = new SimpleDateFormat(strDateFormat);

  Date nextBusinessDay = calendar.getTime();
  System.out.println(sdf.format(nextBusinessDay).toUpperCase());
  if(exceptionDays.contains(sdf.format(nextBusinessDay).toUpperCase())){
      if(sdf.format(nextBusinessDay).toUpperCase().equals("FRIDAY")){
          calendar.add(Calendar.DATE, 3);
      }else if(sdf.format(nextBusinessDay).toUpperCase().equals("SATURDAY")){
          calendar.add(Calendar.DATE, 2);
      } else
          calendar.add(Calendar.DATE, 1);


   nextBusinessDay = calendar.getTime();
  }
  DateFormat df = new SimpleDateFormat("dd-MMM-yy");
    String format = df.format(nextBusinessDay.getTime());
  System.out.println("Today            : " + df.format(today));
  try {
    System.out.println("Next business day: " + df.parse(format));

      System.out.println("Next business day: " + df.format(nextBusinessDay));
Please ignore above logic if it looks clumsy.
解决方案
Simple use Calendar
List<Integer>  avoidingDays = new ArrayList<Integer>();
avoidingDays.add(Calendar.MONDAY);
Calendar cal = Calendar.getInstance();
while(avoidingDays.contains(cal.get(Calendar.DAY_OF_WEEK)) ){cal.add(Calendar.DATE, 1}
return cal;


                        
这篇关于获取下一个有效日期的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！