如何使用内置Date类节省时间？ [英] How can you save time by using the built in Date class?

问题描述

这个问题的意图是使用内置的Date类来收集日期/时间计算的解决方案，而不是编写很多复杂的函数。

The intention of this question is to gather solutions to date / time calculation using the built in Date class instead of writing long complicated functions.

我会写一些回答自己，如果有人提出了非常聪明的事情，接受一个答案。但是这主要是作为一个解决方案的集合，因为我经常看到处理日期过于复杂的代码。

I’ll write some answers myself, and accept an answer if anyone comes up with something very clever. But this is mostly meant as a collection of solutions, since I often see overly complicated code for handling dates.

请记住，这是不对于日期类不能做的事情的长期解决方案。

Please remember this is not for long solutions for things the Date class can not do.

一个好的开始点是这里找到的参考：
http://help.adobe.com/en_US/AS3LCR/Flash_10.0/Date.html

A good place to start is the reference found here: http://help.adobe.com/en_US/AS3LCR/Flash_10.0/Date.html

推荐答案

要正确比较您需要使用getTime（）函数的日期，它将为您提供自1月以来的毫秒数1，1970.这样可以轻松地比较日期，稍后的日期会返回一个更大的值。

To properly compare to dates you need to use the getTime() function, it will give you the time in milliseconds since January 1, 1970. Which makes it easy to compare to dates, a later date will return a larger value.

您可以从另一个中减去一个来获得差异，但是不幸的是没有内置的时间跨度类来处理这个干净的;您将不得不使用一些数学来将差异正确地呈现给用户（例如，将差异与一天中的毫秒数相差以获得差异）。

You can subtract one from the other to get the difference, but unfortunately there is no built in time span class to handle this cleanly; you will have to use a bit of math to present the difference properly to the user (eg. dividing the difference with the number milliseconds in a day to get the difference in days).

var date1:Date = new Date(1994, 12, 24);
var date2:Date = new Date(1991, 1, 3);
if(date1.getTime() > date2.getTime())
    trace("date1 is after date2");
else
    trace("date2 is after or the same as date1");

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