需要在一年内获得所有星期一的日期 [英] Need to get the dates of all mondays in a year

问题描述

我需要在每周的基础上对数据进行排序，所有这些都是日志文件中的日期。
因此，为了整理每周的数据，我想创建一个列表，其中包含给定年份的所有星期一的日期。我已经尝试了一些工作，而我目前唯一的想法就是使用ncal和年份作为循环遍历所有月份，并提取所有的星期一。是不是有更有效的方式？

解决方案

要获取所有的星期一，通过获取所有日期和周一过滤： p>

 为'seq 0 365'
 do date -d+ $ i day
 done | grep Mon 
  

当然，你也可以每星期一，持续增加7天。 >

I need to sort data on a weekly base and all i have are dates in a logfile. Therefore to sort out data per week i would like to create a list with the dates of all mondays for a given year. I have tried to work something out and the only idea i currently have is to use ncal with year and month as argument looping over all months and extracting all mondays. Isn't there a more efficient way?

解决方案

To get all mondays, by getting all dates and filtering by Mondays:

for i in `seq 0 365`
    do date -d "+$i day"
done | grep Mon

Of course, you could also take a monday and keep incrementing by 7 days.

这篇关于需要在一年内获得所有星期一的日期的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！