PHP使用函数在给定的小时内添加两个小时 [英] PHP Add two hours to a date within given hours using function
问题描述
如何构建条件，仅在上午08:30至晚上18:30（不包括星期六和星期日）之间添加两个小时？
如果接近边界的时间（例如星期二17:30），则应将左边的时间加到下一个有效时间段的开头。
$ b例如：如果给定的日期是星期二的17:30，则两个小时的增加将导致周三的9:30（17:30 + 1小时= 18:30，8:30 +剩余的时间） 1小时= 9:30）。或者如果给定的日期是星期五17:00，结果将是星期一（17:00星期五+ 1.5小时= 18:30，星期一8:30 +剩余时间.5小时= 9:00）9:00
我知道如何简单地添加两个小时，如下所示：
$ idate1 = strtotime（$ _ POST ['date']）;
$ time1 = date（'Y-m-d G：i'，strtotime（'+ 120 minutes'，$ idate1））;
$ _POST ['due_date'] = $ time1;
我已经尝试过这个功能，除了当我使用日期（2013-11 -26 12:30）他给我（2013-11-27 04:30:00）
问题是与12:30
function addRollover（$ givenDate，$ addtime）{
$ starttime = 8.5 * 60; //开始时间（分钟）（小时* 60）
$ endtime = 18.5 * 60; //结束时间（分钟）（小时* 60）
$ givenDate = strtotime（$ givenDate）;
//获取给定时间的日期部分
$ givenDay = strtotime（'today'，$ givenDate）;
//计算今天的结束是
$ maxToday = strtotime（+ $ endtime minutes，$ givenDay）;
//计算下一个周期的开始
$ nextPeriod = strtotime（tomorrow，$ givenDay）; //将其设置为第二天
$ nextPeriod = strtotime（+ $ starttime minutes，$ nextPeriod）; //并添加起始时间
//如果是周末，将其冲击到星期一
if（date（D，$ nextPeriod）==Sat）{
$ nextPeriod = strtotime（+ 2天，$ nextPeriod）;
}
//将时间段添加到新的一天
$ newDate = strtotime（+ $ addtime，$ givenDate）;
// print$ givenDate - > $ newDate\\\
;
// print$ maxToday\\\
;
//将新小时作为十进制（加上分钟/ 60）
$ hourfrac = date（'H'，$ newDate）+ date（'i'，$ newDate）/ 60;
// print$ hourfrac\\\
;
//检查我们是否在需要的范围之外
if（$ hourfrac< $ starttime || $ hourfrac> $ endtime）{
//我们是在范围之外，找到余数并将其添加到
$ remaining = $ newDate - $ maxToday;
// print$ remaining\\\
;
$ newDate = $ nextPeriod + $余数;
}
return $ newDate;
}
我不知道你仍然需要这个，但在这里呢。 需要PHP 5.3或更高版本
<？php
function addRollover（$ givenDate， $ addtime）{
$ datetime = new DateTime（$ givenDate）;
$ datetime-> modify（$ addtime）;
if（in_array（$ datetime-> format（'l'），array（'Sunday'，'Saturday'））||
17< $ datetime->格式（'G'）||
（17 === $ datetime->格式（'G'）&& 30< $ datetime->格式（'G'）
）{
$ endofday = clone $ datetime;
$ endofday-> setTime（17,30）;
$ interval = $ datetime-> diff（$ endofday）;
$ datetime-> add（new DateInterval（'P1D'））;
if（in_array（$ datetime-> format（'l'），array（'Saturday'，'Sunday'）））{
$ datetime-> modify（'next Monday'）;
}
$ datetime-> setTime（8,30）;
$ datetime-> add（$ interval）;
}
return $ datetime;
}
$ future = addRollover（'2014-01-03 15:15:00'，'+4小时'）;
echo $ future-> format（'Y-m-d H：i：s'）;
以下是对发生的情况的解释：
-
首先我们创建一个表示我们的开始日期/时间的DateTime对象
-
然后我们添加指定数量的时间到（支持的日期和时间格式）
-
我们检查是否是一个周末，6PM后，或在超过30分钟（例如下午5:30之后）的下午5点的时间内，
-
如果是，我们克隆我们的datetime对象并将其设置为5:30 PM
-
然后我们得到差异在结束时间（下午5:30）和修改时间之间作为 DateInterval对象< a>
-
然后我们进入第二天
-
如果第二天我们星期六进入第二天
-
如果第二天是星期天，我们进入第二天
-
然后我们将时间设定为上午8:30。
-
然后，我们将结束时间（下午5:30）和修改时间我们的日期时间对象
-
我们从函数返回对象
How would I structure the conditions to add two hours only to dates between 08:30 in the morning until 18:30 of the evening, excluding Saturday and Sunday?
In the case that a time near the border (e.g. 17:30 on Tuesday) is given, the left over time should be added to the beginning of the next "valid" time period.
For example: if the given date was in 17:30 on Tuesday, the two hour addition would result in 9:30 on Wednesday (17:30 + 1 hour = 18:30, 8:30 + the remainder 1 hour = 9:30). Or if the given date was in 17:00 on Friday, the result would be 9:00 on Monday (17:00 Friday + 1.5 hours = 18:30, 8:30 Monday + the remainder .5 hours = 9:00)
I know how to simply add two hours, as follows:
$idate1 = strtotime($_POST['date']);
$time1 = date('Y-m-d G:i', strtotime('+120 minutes', $idate1));
$_POST['due_date'] = $time1;
i have tried this this function and it works great except when i use a date like ( 2013-11-26 12:30 ) he gives me ( 2013-11-27 04:30:00 ) the problem is with 12:30
function addRollover($givenDate, $addtime) {
$starttime = 8.5*60; //Start time in minutes (decimal hours * 60)
$endtime = 18.5*60; //End time in minutes (decimal hours * 60)
$givenDate = strtotime($givenDate);
//Get just the day portion of the given time
$givenDay = strtotime('today', $givenDate);
//Calculate what the end of today's period is
$maxToday = strtotime("+$endtime minutes", $givenDay);
//Calculate the start of the next period
$nextPeriod = strtotime("tomorrow", $givenDay); //Set it to the next day
$nextPeriod = strtotime("+$starttime minutes", $nextPeriod); //And add the starting time
//If it's the weekend, bump it to Monday
if(date("D", $nextPeriod) == "Sat") {
$nextPeriod = strtotime("+2 days", $nextPeriod);
}
//Add the time period to the new day
$newDate = strtotime("+$addtime", $givenDate);
//print "$givenDate -> $newDate\n";
//print "$maxToday\n";
//Get the new hour as a decimal (adding minutes/60)
$hourfrac = date('H',$newDate) + date('i',$newDate)/60;
//print "$hourfrac\n";
//Check if we're outside the range needed
if($hourfrac < $starttime || $hourfrac > $endtime) {
//We're outside the range, find the remainder and add it on
$remainder = $newDate - $maxToday;
//print "$remainder\n";
$newDate = $nextPeriod + $remainder;
}
return $newDate;
}
I don't know if you still need this but here it is anyway. Requires PHP 5.3 or higher
<?php
function addRollover($givenDate, $addtime) {
$datetime = new DateTime($givenDate);
$datetime->modify($addtime);
if (in_array($datetime->format('l'), array('Sunday','Saturday')) ||
17 < $datetime->format('G') ||
(17 === $datetime->format('G') && 30 < $datetime->format('G'))
) {
$endofday = clone $datetime;
$endofday->setTime(17,30);
$interval = $datetime->diff($endofday);
$datetime->add(new DateInterval('P1D'));
if (in_array($datetime->format('l'), array('Saturday', 'Sunday'))) {
$datetime->modify('next Monday');
}
$datetime->setTime(8,30);
$datetime->add($interval);
}
return $datetime;
}
$future = addRollover('2014-01-03 15:15:00', '+4 hours');
echo $future->format('Y-m-d H:i:s');
Here's an explanation of what's going on:
First we create a DateTime object representing our starting date/time
We then add the specified amount of time to it (see Supported Date and Time Formats)
We check to see if it is a weekend, after 6PM, or in the 5PM hour with more than 30 minutes passed (e.g. after 5:30PM)
If so we clone our datetime object and set it to 5:30PM
We then get the difference between the end time (5:30PM) and the modified time as a DateInterval object
We then progress to the next day
If the next day is a Saturday we progress to the next day
If the next day is a Sunday we progress to the next day
We then set our time to 8:30AM
We then add our difference between the end time (5:30PM) and the modified time to our datetime object
We return the object from the function
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