在Python中排序日期列表 [英] Sorting a list of dates in Python

问题描述

我在python中列出了一个列表，名称是创建日期的目录;

I have a list in python that is directories who's names are the date they were created;

import os
ConfigDir = "C:/Config-Archive/"
for root, dirs, files in os.walk(ConfigDir):
    if len(dirs) == 0: # This directory has no subfolder
        ConfigListDir = root + "/../" # Step back up one directory
        ConfigList = os.listdir(ConfigListDir)
        print(ConfigList)

['01-02-2014', '01-03-2014', '01-08-2013', '01-09-2013', '01-10-2013']

我想要最新的目录是例如 01-03-2014 ，第二个列表。日期是DD-MM-YYYY。

I want the most recent directory which is that example is 01-03-2014, the second in the list. The dates are DD-MM-YYYY.

可以使用lamba排序键排序，还是应该简单地点击并写一个简单的排序函数？

Can this be sorted using the lamba sort key or should I just take the plunge and write a simple sort function?

推荐答案

您可以在排序键中解析日期：

You'd parse the date in a sorting key:

from datetime import datetime

sorted(ConfigList, key=lambda d: datetime.strptime(d, '%d-%m-%Y'))

演示：

>>> from datetime import datetime
>>> ConfigList = ['01-02-2014', '01-03-2014', '01-08-2013', '01-09-2013', '01-10-2013']
>>> sorted(ConfigList, key=lambda d: datetime.strptime(d, '%d-%m-%Y'))
['01-08-2013', '01-09-2013', '01-10-2013', '01-02-2014', '01-03-2014']

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