将PHP模糊时间转换为Javascript？ [英] Converting PHP Fuzzy time to Javascript?

问题描述

我有一个PHP函数做模糊时间（也就是前面的）。

I have a php function to do fuzzy time (aka time ago).

这是在从服务器端构建表时使用的，但现在我们正在添加通过JavaScript的新项目到表中，我们有能力选择一个日期，因此我需要在Javascript中复制功能，但它接受格式为 YYYY-MM-DD eg 2012-12-14 。

This is used when building a table from the server side, however now we are adding new items to the table through JavaScript, and we have the ability to select a date, therefore I need to duplicate the functionality in Javascript but have it accept the date in the format YYYY-MM-DD e.g. 2012-12-14.

我将开始工作，但我在Javascript中的日期很糟糕已经发布在这里，有人可以更快地执行。

I shall begin working on it, but I am terrible with dates in Javascript so have posted it here incase someone can do it faster.

功能如下：

/**
 * Convert date into a 'fuzzy' format
 *   -  15 minutes ago,  3 days ago, etc.
 * Pass a unix timestamp or a string to parse to a date.
 * @param string|number
 * @return string
 */
function fuzzyTime($date_from, $invalid_date = 'a long time ago') {

    $_time_formats = array(
        array(60, 'just now'),
        array(90, '1 minute'),
        array(3600, 'minutes', 60),
        array(5400, '1 hour'),
        array(86400, 'hours', 3600),
        array(129600, '1 day'),
        array(604800, 'days', 86400),
        array(907200, '1 week'),
        array(2628000, 'weeks', 604800),
        array(3942000, '1 month'),
        array(31536000, 'months', 2628000),
        array(47304000, '1 year'),
        array(3153600000, 'years', 31536000),
    );

    $now = time(); // current unix timestamp

    // if a number is passed assume it is a unix time stamp
    // if string is passed try and parse it to unix time stamp
    if (is_numeric($date_from)) {
        $dateFrom = $date_from;
    } elseif (is_string($date_from)) {
        $dateFrom = strtotime($date_from);
    }

    $difference = $now - $dateFrom; // difference between now and the passed time.
    $val = ''; // value to return

    if ($dateFrom <= 0) {
        $val = $invalid_date;
    } else {
        //loop through each format measurement in array
        foreach ($_time_formats as $format) {
            // if the difference from now and passed time is less than first option in format measurment
            if ($difference < $format[0]) {
                //if the format array item has no calculation value
                if (count($format) == 2) {
                    $val = $format[1] . ($format[0] === 60 ? '' : ' ago');
                    break;
                } else {
                    // divide difference by format item value to get number of units
                    $val = ceil($difference / $format[2]) . ' ' . $format[1] . ' ago';
                    break;
                }
            }
        }
    }
    return $val;
}

这是我到目前为止，但它返回83年之前

This is what I have so far, but it returns 83 years ago

var date = '2012-11-14';

console.log(fuzzyTime(date));

function fuzzyTime($date_from, $invalid_date) {

    if($invalid_date === undefined){
        $invalid_date = 'a long time ago';
    }

    var $_time_formats = [
        [60, 'just now'],
        [90, '1 minute'],
        [3600, 'minutes', 60],
        [5400, '1 hour'],
        [86400, 'hours', 3600],
        [129600, '1 day'],
        [604800, 'days', 86400],
        [907200, '1 week'],
        [2628000, 'weeks', 604800],
        [3942000, '1 month'],
        [31536000, 'months', 2628000],
        [47304000, '1 year'],
        [3153600000, 'years', 31536000]
    ];

    var $now = new Date(); // current unix timestamp
    var $dateFrom = new Date($date_from);

    var $difference = Math.abs(new Date() - $dateFrom);

    var $val = ''; // value to return

    if ($dateFrom <= 0) {
        $val = $invalid_date;
    } else {
        for (var i = 0; i < $_time_formats.length; i++) {
            var $format = $_time_formats[i];

            if ($difference < $format[0]) {
                //if the format array item has no calculation value
                if ($format.length == 2) {
                    $val = $format[1] + ($format[0] === 60 ? '' : ' ago');
                    break;
                } else {
                    // divide difference by format item value to get number of units
                    $val = Math.ceil($difference / $format[2]) + ' ' + $format[1] + ' ago';
                    break;
                }
            }
        }

    }
    return $val;
}

推荐答案

p>

Ah got it,

var date = '2012-12-14 17:52:00';

console.log(fuzzyTime(date));

function fuzzyTime(date_from, invalid_date) {

    if (invalid_date === undefined) {
        invalid_date = 'a long time ago';
    }

    var time_formats = [
        [60, 'just now'],
        [90, '1 minute'],
        [3600, 'minutes', 60],
        [5400, '1 hour'],
        [86400, 'hours', 3600],
        [129600, '1 day'],
        [604800, 'days', 86400],
        [907200, '1 week'],
        [2628000, 'weeks', 604800],
        [3942000, '1 month'],
        [31536000, 'months', 2628000],
        [47304000, '1 year'],
        [3153600000, 'years', 31536000]
    ];

    var now = new Date().getTime(); // current unix timestamp
    var dateFrom = new Date(date_from.replace('-','/')).getTime();

    var difference = Math.abs(now - dateFrom)/1000;

    var val = ''; // value to return

    if (dateFrom <= 0) {
        val = invalid_date;
    } else {
        for (var i = 0; i < time_formats.length; i++) {
            var format = time_formats[i];

            if (difference < format[0]) {
                //if the format array item has no calculation value
                if (format.length == 2) {
                    val = format[1] + (format[0] === 60 ? '' : ' ago');
                    break;
                } else {
                    // divide difference by format item value to get number of units
                    val = Math.ceil(difference / format[2]) + ' ' + format[1] + ' ago';
                    break;
                }
            }
        }

    }
    return val;
}

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