需要在Objective-C iOS中将自定义时间戳转换为不同的格式 [英] Need to convert custom timestamp to different format in Objective-C iOS

问题描述

我有一个字符串2012-06-04，很难将其转换为： 2012年6月4日。

谢谢

解决方案

p>一种方法是使用 NSDateFormatter ，然后使用2012年6月4日格式将NSDate转换为字符串：

  NSString * input = @2012-06-04; 
 
 NSDateFormatter * df = [[NSDateFormatter alloc] init]; 
 [df setDateFormat：@yyyy-MM-dd]; 
 NSDate * date = [df dateFromString：input]; 
 [df setDateFormat：@MMMM d，yyyy]; 
 
 return [df stringFromDate：date]; 
  

格式字符串的语法在 UTS＃35 。

I have a string "2012-06-04" and am having a hard time converting it to: June 4, 2012.

Is there a quick way to transform this? I come from a ruby world where you would convert everything to seconds and that back out to the format you need it. Is there a reference that shows how to do that?

Thanks

解决方案

One way to do so is to convert the string to an NSDate using the NSDateFormatter with the 2012-06-04 format, and then convert the NSDate back to a string using the June 4, 2012 format:

NSString* input = @"2012-06-04";

NSDateFormatter* df = [[NSDateFormatter alloc] init];
[df setDateFormat:@"yyyy-MM-dd"];
NSDate* date = [df dateFromString:input];
[df setDateFormat:@"MMMM d, yyyy"];

return [df stringFromDate:date];

The format string's syntax is described in UTS #35.

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