jquery datepicker多个实例 [英] jquery datepicker multiple instances

问题描述

我已经提出了一个RequestForQuote表单，其中我给出了可以添加新职位以获得RFQ的功能。

I have made a RequestForQuote form, in which I give the possebility to add new positions to get RFQ'ed.

在基础知识中，这很容易通过PHP在我的情况下工作真的很好你可能想看看。可以在以下网址找到：我的网站

In basics this is quite easy done via PHP in my case. Work realy fine. You may want to have a look. It is to be found at: my website

现在我感染了jquery病毒，只想添加datepicker ui（对于我们从他们的网页获得的最新版本）。

Now I got infected with the jquery-virus and simply wanted to add the datepicker ui (for the latest version I got from their webpage).

<input type="text" size="10" id="deldate[] 
     class="datepicker" value="<?php echo $_REQUEST['deldate'][$k]; ?>" />

$ k来自一个php $ k = 0; $ k <= $ NoPos; $ k ++）循环

$k is from a php for($k=0;$k<=$NoPos;$k++) loop

JavaScript代码工作如下：

the javascript code work is like:

$(function() {
$('input').filter('.datepicker').datepicker({
        showOn: 'button', 
        buttonImage: 'calender/media/cal.gif', 
        buttonImageOnly: true,
        firstDay: 1,
        dateFormat: 'yy-mm-dd', 
        minDate: 0, maxDate: '+4Y'});

}); 

在浏览器中看起来很不错，你会显示，我可以选择一个日期。

An in the browswer it looks quite nice, the ui shows up, I cann select a date.

但是...

如果我在表单中添加了另一个位置，这是通过PHP完成的，所以我必须提交表单来计数$ NoPos，以前的无效日期是丢失，我有一个空白的输入字段。

if I add another position to the form, which is done via PHP, so I have to submit the form to count $NoPos up, the formerly inersted date(s) is lost and I have a blank input-field.

现在有
onSubmit：function（dateText）我可以得到选定的日期，但是我在accessi中失败了输入正确的输入字段来放入日期。

now with the onSubmit: function(dateText) I can get the selected date. However I am failing in accessing the correct input field to put the date in.

所以我的问题很简单：我做错了什么？如果evrything是罚款，请有人请告诉我如何解决这个..

So my question is simple: What am I doing wrong? If evrything is fine then someone would please please tell me how I can solve this..

我有一些东西，如：

for (var i=0;i<=NoPos;i++) {
    var tag = "#deldate"+i;
    $(tag).datepicker({ ... });
}

并使用php到< input type = textsize =10id =lieferdat<？php echo $ k;？> class =datepicker/>

非常感谢您的耐心阅读本文...

Many thanks for your assumed patience to read through this...

，还有更多的谢谢给出的任何提示。

and many more thanks for any hints given

Cheers Daniel

Cheers Daniel

推荐答案

我正在寻找同样的自己，我想我发现这个技巧：
$（'input' ）.filter（'。datepickerclass'）。datepicker（）

和相关的输入元素：

class = datepickerclass

i was looking for the same myself, and i think i found the trick to it: $('input').filter('.datepickerclass').datepicker()
and on the relevant input elements:
class="datepickerclass"

我看到上面你尝试过类似的东西，但只是遵循食谱（该链接）为我工作。

i see above you tried something similar, but just following the recipe (of that link) worked for me.

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