如何按datetime列分区表? [英] how to partition a table by datetime column?
问题描述
CREATE TABLE raw_log_2011_4(
id bigint(20) NOT NULL AUTO_INCREMENT,
logid char(16)NOT NULL,
tid char(16)NOT NULL,
reporterip char(46)DEFAULT NULL,
ftime datetime DEFAULT NULL,
KEY id(id)
)ENGINE = InnoDB AUTO_INCREMENT = 286802795 DEFAULT CHARSET = utf8
PARTITION BY hash(day(ftime))分区31;
但是当我选择某一天的数据时,找不到分区。select语句就像这是:
解释分区select * from raw_log_2011_4 where day(ftime)= 30;
当我使用另一个语句,它可以找到分区,但我无法选择某一天的数据
解释分区select * from raw_log_2011_4其中ftime ='2011-03-30';
有没有人告诉我如何选择某一天的数据并利用分区。谢谢!
HASH分区是一个非常糟糕的想法,使用datetime列,因为它不能使用分区修剪。从MySQL文档:
修剪只能用于由
HASH或KEY分区的整数列的整数列。例如,表t4上的此查询不能使用修剪
,因为dob是DATE列:
SELECT * FROM t4 WHERE dob> ='2001-04-14'AND dob< ='2005-10-15';
但是,如果表在INT列中存储年值,一个
查询的WHERE year_col> = 2001 AND year_col< = 2005可以
修剪。
所以您可以在额外的INTEGER列中存储TO_DAYS(DATE())的值以使用修剪。
另一个选项是使用RANGE分区:
CREATE TABLE raw_log_2011_4(
id bigint(20)NOT NULL AUTO_INCREMENT,
logid char(16)NOT NULL,
tid char(16)NOT NULL,
reporterip char(46)DEFAULT NULL,
ftime datetime DEFAULT NULL,
KEY id(id)
)ENGINE = InnoDB AUTO_INCREMENT = 286802795 DEFAULT CHARSET = utf8
按范围划分(TO_DAYS(datetime))(
PARTITION p20110401 VALUES LESS THAN(TO_DAYS('2011-04-02')),
PARTITION p20110402 VALUES LESS THAN TO_DAYS('2011-04-03')),
PARTITION p20110403 VALUES LESS THAN(TO_DAYS('2011-04-04')),
PARTITION p20110404价值不超过(TO_DAYS('2011-04-05')),
...
PARTITION p20110426值不超过(TO_DAYS('2011-04-27')) ,
PARTITION p20110427价值不超过(TO_DAYS('2011-04-28')),
PARTITION p20110428价值不超过(TO_DAYS('2011-04-29')),
PARTITION p20110429值小于(TO_DAYS('2011-04-30')),
分段未来值小于MAXVALUE
);
现在以下查询将仅使用分区p20110403:
SELECT * FROM raw_log_2011_4 WHERE ftime ='2011-04-03';
I want to partition a mysql table by datetime column. One day a partition.The create table scripts is like this:
CREATE TABLE raw_log_2011_4 (
id bigint(20) NOT NULL AUTO_INCREMENT,
logid char(16) NOT NULL,
tid char(16) NOT NULL,
reporterip char(46) DEFAULT NULL,
ftime datetime DEFAULT NULL,
KEY id (id)
) ENGINE=InnoDB AUTO_INCREMENT=286802795 DEFAULT CHARSET=utf8
PARTITION BY hash (day(ftime)) partitions 31;
But when I select data of some day.It could not locate the partition.The select statement is like this:
explain partitions select * from raw_log_2011_4 where day(ftime) = 30;
when i use another statement,it could locate the partition,but I coluld not select data of some day.
explain partitions select * from raw_log_2011_4 where ftime = '2011-03-30';
Is there anyone tell me How I could select data of some day and make use of partition.Thanks!
Partitions by HASH is a very bad idea with datetime columns, because it cannot use partition pruning. From the MySQL docs:
Pruning can be used only on integer columns of tables partitioned by HASH or KEY. For example, this query on table t4 cannot use pruning because dob is a DATE column:
SELECT * FROM t4 WHERE dob >= '2001-04-14' AND dob <= '2005-10-15';
However, if the table stores year values in an INT column, then a query having WHERE year_col >= 2001 AND year_col <= 2005 can be pruned.
So you can store the value of TO_DAYS(DATE()) in an extra INTEGER column to use pruning.
Another option is to use RANGE partitioning:
CREATE TABLE raw_log_2011_4 (
id bigint(20) NOT NULL AUTO_INCREMENT,
logid char(16) NOT NULL,
tid char(16) NOT NULL,
reporterip char(46) DEFAULT NULL,
ftime datetime DEFAULT NULL,
KEY id (id)
) ENGINE=InnoDB AUTO_INCREMENT=286802795 DEFAULT CHARSET=utf8
PARTITION BY RANGE( TO_DAYS(datetime) ) (
PARTITION p20110401 VALUES LESS THAN (TO_DAYS('2011-04-02')),
PARTITION p20110402 VALUES LESS THAN (TO_DAYS('2011-04-03')),
PARTITION p20110403 VALUES LESS THAN (TO_DAYS('2011-04-04')),
PARTITION p20110404 VALUES LESS THAN (TO_DAYS('2011-04-05')),
...
PARTITION p20110426 VALUES LESS THAN (TO_DAYS('2011-04-27')),
PARTITION p20110427 VALUES LESS THAN (TO_DAYS('2011-04-28')),
PARTITION p20110428 VALUES LESS THAN (TO_DAYS('2011-04-29')),
PARTITION p20110429 VALUES LESS THAN (TO_DAYS('2011-04-30')),
PARTITION future VALUES LESS THAN MAXVALUE
);
Now the following query will only use partition p20110403:
SELECT * FROM raw_log_2011_4 WHERE ftime = '2011-04-03';
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