Python时间差异 [英] Python time differences

问题描述

我有两个时间对象。

示例

time.struct_time(tm_year=2010, tm_mon=9, tm_mday=24, tm_hour=19, tm_min=13, tm_sec=37, tm_wday=4, tm_yday=267, tm_isdst=-1)

time.struct_time(tm_year=2010, tm_mon=9, tm_mday=25, tm_hour=13, tm_min=7, tm_sec=25, tm_wday=5, tm_yday=268, tm_isdst=-1)

我该怎么办？
我只需要几分钟和几秒钟，以及这两个的持续时间。

I want to have the difference of those two. How could I do that? I need minutes and seconds only, as well as the duration of those two.

推荐答案

时间实例不支持减法运算。考虑到解决这个问题的一种方法是将时间转换为从时代开始的秒数，然后找到差异，请使用：

Time instances do not support the subtraction operation. Given that one way to solve this would be to convert the time to seconds since epoch and then find the difference, use:

>>> t1 = time.localtime()
>>> t1
time.struct_time(tm_year=2010, tm_mon=10, tm_mday=13, tm_hour=10, tm_min=12, tm_sec=27, tm_wday=2, tm_yday=286, tm_isdst=0)
>>> t2 = time.gmtime()
>>> t2
time.struct_time(tm_year=2010, tm_mon=10, tm_mday=13, tm_hour=4, tm_min=42, tm_sec=37, tm_wday=2, tm_yday=286, tm_isdst=0)

>>> (time.mktime(t1) - time.mktime(t2)) / 60
329.83333333333331

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