如何将st_mtime（从stat函数获取）转换为字符串或字符 [英] How to convert st_mtime (which get from stat function) to string or char

问题描述

我需要将st_mtime转换为字符串格式以传递给java层，我尝试使用这个例子 http://www.cplusplus.com/forum/unices/10342/ ，但编译器会产生错误

I need to convert st_mtime to string format for passing it to java layer, i try to use this example http://www.cplusplus.com/forum/unices/10342/ but compiler produce errors

无效转换从'long unsigned int *'到'const time_t * {aka
long int const *}'

invalid conversion from 'long unsigned int*' to 'const time_t* {aka long int const*}'

初始化参数1'tm * localtime（const time_t *）'
[-fpermissive]

initializing argument 1 of 'tm* localtime(const time_t*)' [-fpermissive]

我做错了什么，如何使用stat函数获取时间创建文件

What i doing wrong, how to get time creation of file using stat function in string presentation.

请帮助。

推荐答案

根据< a href =http://www.kernel.org/doc/man-pages/online/pages/man2/stat.2.html =noreferrer> stat（2）手册页， st_mtime 字段是一个 time_t （即在阅读 time（7）手册页，自以来的几秒钟unix Epoch ）。

According to the stat(2) man page, the st_mtime field is a time_t (i.e. after reading the time(7) man page, a number of seconds since the unix Epoch).

您需要 localtime（3）将 time_t 转换为 struct tm 在当地时间，然后， strftime（3）将其转换为 char * 字符串。

You need localtime(3) to convert that time_t to a struct tm in local time, then, strftime(3) to convert it to a char* string.

所以你可以编码类似于：

So you could code something like:

time_t t = mystat.st_mtime;
struct tm lt;
localtime_r(&t, &lt);
char timbuf[80];
strftime(timbuf, sizeof(timbuf), "%c", &lt);

然后使用 timbuf 或许以$ $ c> strdup -ing it。

then use timbuf perhaps by strdup-ing it.

NB。我使用 localtime_r ，因为它更线程友好。

NB. I am using localtime_r because it is more thread friendly.

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