如何将系数转换为R中的DateTime？ [英] how to convert factor into DateTime in R?

问题描述

这个问题对于一些人来说可能很简单，但是因为我是R的初学者，而是忍受我。

This question might be simple for some of you but bear with me since I'm a beginner in R.

我有一个数据框，它有一个因子列称为时间）包含DateTime数据如下：

I have a dataframe that has a factor column (called time) containing DateTime data as the following:

time
01/01/2011 00:10
02/01/2011 03:00
03/01/2011 05:00
04/01/2011 10:03

我想将此列转换为R中的DateTime列。我搜索并尝试了一些功能，但它给出了NA结果。以下功能是我尝试过的功能：

I want to convert this column into DateTime column in R. I searched and tried some functions but it gives me 'NA' results. The following functions are those I tried:

> dataframe1$datetime <- as.POSIXlt(as.character(dataframe1$time), format="%d/%m/%Y %H:%M")
> dataframe1$datetime <- as.POSIXlt(strptime(dataframe1$time), format="%d/%m/%Y %H:%M")
> dataframe1$datetime <- as.POSIXlt(dataframe1$time, format="%d/%m/%Y %H:%M")
> dataframe1$datetime <- as.chron(dataframe1$time, "%d/%m/%Y %H:%M")

我不知道还有什么要尝试的。我希望理想地添加三列，即日期时间，日期和时间。非常感谢您的帮助。

I don't know what else to try. I want ideally to add three columns namely datetime, date, and time. Your help is much appreciated.

非常感谢advacne。

Many thanks in advacne.

推荐答案

尝试：

dataframe1$datetime <- strptime(x = as.character(dataframe1$datetime),
                                format = "%d/%m/%Y %H:%M")

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