Python中的代码的定时块，而不会放在一个函数中 [英] timing block of code in Python without putting it in a function

问题描述

我想把一段代码放在一个单独的函数中。例如：

I'd like to time a block of code without putting it in a separate function. for example:

def myfunc:
  # some code here
  t1 = time.time()
  # block of code to time here
  t2 = time.time()
  print "Code took %s seconds." %(str(t2-t1))

但是，我想用timeit模块在一个更干净的方式，但我不想为代码块单独的功能。

however, I'd like to do this with the timeit module in a cleaner way, but I don't want to make a separate function for the block of code.

谢谢。

推荐答案

您可以使用与语句一起执行此操作。例如：

You can do this with the with statement. For example:

import time    
from contextlib import contextmanager

@contextmanager  
def measureTime(title):
    t1 = time.clock()
    yield
    t2 = time.clock()
    print '%s: %0.2f seconds elapsed' % (title, t2-t1)

要像这样使用：

def myFunc():
    #...

    with measureTime('myFunc'):
        #block of code to time here

    #...

这篇关于Python中的代码的定时块，而不会放在一个函数中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！