在给定的日期添加n个工作日，忽略假日和周末在python [英] Add n business days to a given date ignoring holidays and weekends in python

问题描述

我想在给定日期添加n（整数）个工作日，添加日期必须避免假期和周末（在工作日内不包括）

I'm trying to add n (integer) working days to a given date, the date addition has to avoid the holidays and weekends (it's not included in the working days)

推荐答案

跳过周末将很容易做这样的事情：

Skipping weekends would be pretty easy doing something like this:

import datetime
def date_by_adding_business_days(from_date, add_days):
    business_days_to_add = add_days
    current_date = from_date
    while business_days_to_add > 0:
        current_date += datetime.timedelta(days=1)
        weekday = current_date.weekday()
        if weekday >= 5: # sunday = 6
            continue
        business_days_to_add -= 1
    return current_date

#demo:
print '10 business days from today:'
print date_by_adding_business_days(datetime.date.today(), 10)

假期的问题是它们因国家或地区，宗教信仰而异等等。您将需要一个用于您的用例的列表/一组假期，然后以类似的方式跳过它们。一个起点可能是苹果为iCal（以ics格式）发布的日历Feed，美国的日期Feed将为 http://files.apple.com/calendars/US32Holidays.ics

The problem with holidays is that they vary a lot by country or even by region, religion, etc. You would need a list/set of holidays for your use case and then skip them in a similar way. A starting point may be the calendar feed that Apple publishes for iCal (in the ics format), the one for the US would be http://files.apple.com/calendars/US32Holidays.ics

您可以使用 icalendar 模块来解析这个。

You could use the icalendar module to parse this.

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