访问Python中的datetime.now()值 [英] Accessing datetime.now() values in Python
问题描述
我想能够在我的程序中实现一个条件,它只运行N个小时,也许用户可以指定N,但是我们不能前进。
$ b $我想我可以使用
datetime.now()
并将以下值存储在变量中, time
>>>时间
>>>> time = datetime.datetime(2013,12,9,21,50,32,405329)
任何关于我如何可以访问( - )之间的第四个字段的想法,看到它是一个字符串?
我的条件将像,而time!= timeEnd
其中timeEnd将是以下值: p>
>>> timeEnd = datetime.datetime(2013,12,9,21 + N,50,32,405329)
谢谢
您可以将 timedelta
添加到 datetime
获得一个新的 datetime
。
>> ;> import datetime
>>>> now = datetime.datetime.now()
>>> end_time = now + datetime.timedelta(hours = 6)
>>>现在打印
2013-12-09 17:03:06.979628
>>> print end_time
2013-12-09 23:03:06.979628
>>>
然后...
while datetime.datetime.now()< end_time:
pass#do work
I want to be able to implement a condition in my program where it would only run for N number of hours, maybe the user could specify N, but let's not jump ahead.
I figured I could use datetime.now()
and store the value below in a variable, time
>>> time
>>> time = datetime.datetime(2013, 12, 9, 21, 50, 32, 405329)
Any ideas on how I can access the fourth field between the (--), seeing as it's a string?
My condition would be something like while time != timeEnd
where timeEnd would be the value of below:
>>> timeEnd = datetime.datetime(2013, 12, 9, 21+N, 50, 32, 405329)
Thanks
You can add a timedelta
to a datetime
to get a new datetime
.
>>> import datetime
>>> now = datetime.datetime.now()
>>> end_time = now + datetime.timedelta(hours=6)
>>> print now
2013-12-09 17:03:06.979628
>>> print end_time
2013-12-09 23:03:06.979628
>>>
Then...
while datetime.datetime.now() < end_time:
pass # do work
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