访问Python中的datetime.now()值 [英] Accessing datetime.now() values in Python

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本文介绍了访问Python中的datetime.now()值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想能够在我的程序中实现一个条件,它只运行N个小时,也许用户可以指定N,但是我们不能前进。


$ b $我想我可以使用 datetime.now()并将以下值存储在变量中, time

 >>>时间
>>>> time = datetime.datetime(2013,12,9,21,50,32,405329)

任何关于我如何可以访问( - )之间的第四个字段的想法,看到它是一个字符串?



我的条件将像,而time!= timeEnd 其中timeEnd将是以下值: p>

>>> timeEnd = datetime.datetime(2013,12,9,21 + N,50,32,405329)



谢谢

解决方案

您可以将 timedelta 添加到 datetime 获得一个新的 datetime

 >> ;> import datetime 
>>>> now = datetime.datetime.now()
>>> end_time = now + datetime.timedelta(hours = 6)
>>>现在打印
2013-12-09 17:03:06.979628
>>> print end_time
2013-12-09 23:03:06.979628
>>>

然后...

  while datetime.datetime.now()< end_time:
pass#do work


I want to be able to implement a condition in my program where it would only run for N number of hours, maybe the user could specify N, but let's not jump ahead.

I figured I could use datetime.now() and store the value below in a variable, time

>>> time 
>>> time = datetime.datetime(2013, 12, 9, 21, 50, 32, 405329)

Any ideas on how I can access the fourth field between the (--), seeing as it's a string?

My condition would be something like while time != timeEnd where timeEnd would be the value of below:

>>> timeEnd = datetime.datetime(2013, 12, 9, 21+N, 50, 32, 405329)

Thanks

解决方案

You can add a timedelta to a datetime to get a new datetime.

>>> import datetime
>>> now = datetime.datetime.now()
>>> end_time = now + datetime.timedelta(hours=6)
>>> print now
2013-12-09 17:03:06.979628
>>> print end_time
2013-12-09 23:03:06.979628
>>> 

Then...

while datetime.datetime.now() < end_time:
    pass # do work

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