将时间输出转换为浮点数变量（Python） [英] Converting Time Output to a Float Variable (Python)

问题描述

来自Tkinter导入的$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ b $ 35.34）
amp = 2.40
pmp = 2.50



signOnSun1 = raw_input（星期日你在什么时间登录）;
signOffSun1 = raw_input（星期日你星期天离开什么时间）;

if（signOnSun1< 0600）：
rate1 = rate1 + amp
elif（signOnSun1> 1100）：
rate1 = rate1 + pmp
elif（signOffSun1> 1800）：
rate1 = rate1 + pmp
else：
rate1 = 35.34

FMT ='％H％M'
timeWorkedSun1 =（（datetime.strptime（signOffSun1，FMT）） - （datetime.strptime（signOnSun1，FMT）））

*我想将timeWorkedSun1转换为一个float，所以我可以将其与rate1相乘，但似乎是我生命中的祸根。任何想法？*

解决方案

timeWorkedSun1 是类型 datetime.timedelta 。调用它的 total_seconds 方法将其转换为第二个数值（然后除以3600，以小时计）。即：

  time_mul_by_hourly_rate =（timeWorkedSun1.total_seconds（）/ 3600.0）* rate1 
  

from Tkinter import *
from datetime import datetime
from datetime import timedelta
import math

rate1 = str(35.34) 
amp = 2.40
pmp = 2.50



signOnSun1 = raw_input("What time did you sign on Sunday: ");
signOffSun1 = raw_input("What time did you sign off Sunday: ");

if (signOnSun1 < 0600):
    rate1 = rate1 + amp
elif (signOnSun1 > 1100):
    rate1 = rate1 + pmp
elif (signOffSun1 > 1800):
    rate1 = rate1 + pmp
else:
    rate1 = 35.34

FMT = '%H%M'    
timeWorkedSun1 =  ( (datetime.strptime(signOffSun1, FMT)) -  (datetime.strptime   (signOnSun1, FMT)))

* I want to convert timeWorkedSun1 to a float so i can multiply it with rate1 but it seems to be the bane of my life. Any ideas?*

解决方案

timeWorkedSun1 is of type datetime.timedelta. Call its total_seconds method to translate it into a number of second (then divide by 3600 to get it in hours-and-fractions). I.e:

time_mul_by_hourly_rate = (timeWorkedSun1.total_seconds() / 3600.0) * rate1

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