无法在自动设置器上设置断点?为什么? [英] Can't set breakpoints on an auto-property setter ? Why?
问题描述
显然,VS 2008不允许在自动属性设置器上设置断点。
Apparently VS 2008 does not allow setting a breakpoint just on the setter of an auto-property.
I.e。如果我定义一个这样的自动属性:
I.e. if I define an auto-property like this:
public int CurrentFramesize
{
get;
protected set;
}
然后尝试在setter行上设置一个断点,属性转为断点红色。
and then try to set a breakpoint on the setter line, the whole auto-property turns breakpoint-red.
这对正常的属性很好,所以任何想法为什么自动属性得到这个特殊的(限制性的)治疗?他们不仅仅是语法糖与具有隐藏支持字段的正常属性?
This works just fine for normal properties, so any idea why auto-properties get this special (restrictive) treatment? Are they more than just syntactic sugar to normal properties with a hidden backing field?
推荐答案
使用Visual Studio 2008,2010,2012:
Using Visual Studio 2008, 2010, 2012:
- 转到Breakpoint窗口
- New-> Break in Function ...
-
对于get,
类型:ClassName.get_CurrentFramesize()
对于集合,键入: ClassName.set_CurrentFramesize(int)
当断点被击中时,您将获得无源,但您将在调用堆栈中获取呼叫位置。
You'll get a "No Source Available" when the breakpoint is hit, but you'll get the calling location in the call stack.
我发现这个解决方案在这里: http://社会.msdn.microsoft.com / Forums / en / vsdebug / thread / b1dd0dc3-e9c1-402a-9c79-a5abf7f7286a
I found this solution here: http://social.msdn.microsoft.com/Forums/en/vsdebug/thread/b1dd0dc3-e9c1-402a-9c79-a5abf7f7286a
另请参见: tomatic属性
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