筛选由代理Ajax请求 [英] Filter ajax request by proxy

问题描述

我有一个代理在那里我想proxify AJAX 请求我发现，code和它的作品很好的：

I have a proxy where i want to proxify ajax requests i have found that code and it works good:

(function() {

        if (window.XMLHttpRequest) {

          function parseURI(url) {
            var m = String(url).replace(/^\s+|\s+$/g, "").match(/^([^:\/?#]+:)?(\/\/(?:[^:@]*(?::[^:@]*)?@)?(([^:\/?#]*)(?::(\d*))?))?([^?#]*)(\?[^#]*)?(#[\s\S]*)?/);
            // authority = "//" + user + ":" + pass "@" + hostname + ":" port
            return (m ? {
              href : m[0] || "",
              protocol : m[1] || "",
              authority: m[2] || "",
              host : m[3] || "",
              hostname : m[4] || "",
              port : m[5] || "",
              pathname : m[6] || "",
              search : m[7] || "",
              hash : m[8] || ""
            } : null);
          }

          function rel2abs(base, href) { // RFC 3986

            function removeDotSegments(input) {
              var output = [];
              input.replace(/^(\.\.?(\/|$))+/, "")
                .replace(/\/(\.(\/|$))+/g, "/")
                .replace(/\/\.\.$/, "/../")
                .replace(/\/?[^\/]*/g, function (p) {
                  if (p === "/..") {
                    output.pop();
                  } else {
                    output.push(p);
                  }
                });
              return output.join("").replace(/^\//, input.charAt(0) === "/" ? "/" : "");
            }

            href = parseURI(href || "");
            base = parseURI(base || "");

            return !href || !base ? null : (href.protocol || base.protocol) +
            (href.protocol || href.authority ? href.authority : base.authority) +
            removeDotSegments(href.protocol || href.authority || href.pathname.charAt(0) === "/" ? href.pathname : (href.pathname ? ((base.authority && !base.pathname ? "/" : "") + base.pathname.slice(0, base.pathname.lastIndexOf("/") + 1) + href.pathname) : base.pathname)) +
            (href.protocol || href.authority || href.pathname ? href.search : (href.search || base.search)) +
            href.hash;

          }

          var proxied = window.XMLHttpRequest.prototype.open;
          window.XMLHttpRequest.prototype.open = function() {
              if (arguments[1] !== null && arguments[1] !== undefined) {
                var url = arguments[1];
                url = rel2abs("' . $url . '", url);
                url = "' . PROXY_PREFIX . '" + url;
                arguments[1] = url;
              }
              return proxied.apply(this, [].slice.call(arguments));
          };

        }

      })();

但问题是，我也有一些 AJAX 的要求，我不需要为 proxyify 但我用 XMLHtt prequest 太...

But the problem is that i also have some ajax request which i dont need to proxyify but i use XMLHttpRequest too...

和问题是我怎么可以过滤我的 AJAX 的要求，而忽略他们的的JavaScript ？

And the question is how can i filter my ajax requests and ignore them in that javascript?

推荐答案

添加一个公共接口来访问代理打开电话：

Add a public interface to access the proxied open call:

var proxied = window.XMLHttpRequest.prototype.open;
window.XMLHttpRequest.prototype.open_noproxy = proxied;

然后就可以调用 XMLHtt prequest :: open_noproxy（）当你想使一个普通的AJAX调用。

Then you can call XMLHttpRequest::open_noproxy() when you want to make a normal AJAX call.

另一种方法是把一个关键词在URL，如 NOPROXY：HTTP：//无论。您更换打开功能可以检查是否URL以 NOPROXY：;如果是的话，它会删除其从URL，然后跳过了code，在调用之前增加了代理preFIX 代理。

Another way would be to put a keyword in the URL, e.g. NOPROXY:http://whatever. Your replacement open function can check whether the URL begins with NOPROXY:; if so, it removes it from the URL and then skips over the code that adds the proxy prefix before calling proxied.

这篇关于筛选由代理Ajax请求的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！