快速排序与Python [英] Quick sort with Python

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本文介绍了快速排序与Python的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我完全新的Python,我想在这上面实现快速排序。 可能有人请帮助我完成我的code?

我不知道如何连接三个数组进行打印。

 高清排序(数组= [12,4,5,6,7,3,1,15]):
    少= []
    等于= []
    更大= []

    如果len(阵列)> 1:
        透视=阵列[0]
        对于x数组:
            如果x<枢:
                less.append(X)
            如果x ==支点:
                equal.append(X)
            如果x>枢:
                greater.append(X)
            排序(少)
            排序(支点)
            排序(大于)
 

解决方案

 高清排序(数组= [12,4,5,6,7,3,1,15]):
    少= []
    等于= []
    更大= []

    如果len(阵列)> 1:
        透视=阵列[0]
        对于x数组:
            如果x<枢:
                less.append(X)
            如果x ==支点:
                equal.append(X)
            如果x>枢:
                greater.append(X)
        #不要忘了返回的东西!
        返回排序(少)+平等+排序(较大)#只需使用+运算符连接列表
    要平等#注意^^^^^没有支点
    其他:#你需要喊得部分在递归的终点 - 当你只有在你的数组的一个元素,就返回数组。
        返回数组
 

I am totally new to python and I am trying to implement quick sort in it. Could someone please help me complete my code?

I do not know how to concatenate the three arrays and printing them.

def sort(array=[12,4,5,6,7,3,1,15]):
    less = []
    equal = []
    greater = []

    if len(array) > 1:
        pivot = array[0]
        for x in array:
            if x < pivot:
                less.append(x)
            if x == pivot:
                equal.append(x)
            if x > pivot:
                greater.append(x)
            sort(less)
            sort(pivot)
            sort(greater)

解决方案

def sort(array=[12,4,5,6,7,3,1,15]):
    less = []
    equal = []
    greater = []

    if len(array) > 1:
        pivot = array[0]
        for x in array:
            if x < pivot:
                less.append(x)
            if x == pivot:
                equal.append(x)
            if x > pivot:
                greater.append(x)
        # Don't forget to return something!
        return sort(less)+equal+sort(greater)  # Just use the + operator to join lists
    # Note that you want equal ^^^^^ not pivot
    else:  # You need to hande the part at the end of the recursion - when you only have one element in your array, just return the array.
        return array

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