Gradle：子模块中抛出类错误的属性？ [英] Gradle: No such property for class error thrown in sub-module?

问题描述

我正在使用依赖项这个答案的-grad-how-do-i-declare-common-dependencies-in-a-one-place。

I am trying to declare the dependencies in my gradle project using the technique described in this answer.

但是当我这样做的时候我收到这个错误：

However when I do so I get this error:

No such property: libraries for class

如何解决这个问题？

依赖性声明为顶级属性 build.gradle ，如下所示：

Dependencies declared as properties at top level build.gradle as follows:

ext.libraries = [


junit: 'junit:junit:4.10'

]

尝试在模块级build.gradle 中检索依赖项（抛出错误）：

Trying to retrieve dependency in module level build.gradle (where error is being thrown):

testCompile([
              libraries.junit
])

错误抛出：

No such property: libraries for class: org.gradle.api.internal.artifacts.dsl.dependencies.DefaultDependencyHandler

推荐答案

1. 在您的顶级 settings.gradle 中，包含您的子项目：

1. In your top level settings.gradle, include your subproject:

include 'subproject'

在你的顶级 build.gradle 定义你的ext属性：

In your top level build.gradle define your ext properties:

ext.libraries = [junit: 'junit:junit:4.10']

它没有作为地图，如果您只使用1个值，但我坚持使用格式。

it does not have to be a map, if you're using just 1 value, but I'm sticking with your formatting.

1. 要在您的子项目build.gradle中使用此选项，请执行以下操作：

1. To use this in your subproject build.gradle:

dependencies{
  testCompile libraries.junit 
}

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