Android:创建一个包含多个选择选项的弹出窗口 [英] Android: create a popup that has multiple selection options

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问题描述

我一直在寻找想知道如何创建一个弹出式窗口或一个对话框,有4个选项可供选择。

I've been searching around trying to figure out how to create a popup or a dialog that has 4 options to choose from.

我看到这张照片在Android开发人员网站:

I see this picture on the Android developer site:

有人知道如何编写像右边的东西吗?我不需要任何图标旁边的文字,我只需要能够从4个选项。

Does anyone know how to code up something like the one on the right? I don't need any icons next to my text, I just need to be able to select from 4 options.

推荐答案

你可以使用要显示的选项创建一个 CharSequence 数组,然后将数组传递给一个 AlertDialog.Builder 与方法 setItems(CharSequence [],DialogInterface.OnClickListener)

You can create a CharSequence array with the options you want to show there and then pass the array to an AlertDialog.Builder with the method setItems(CharSequence[], DialogInterface.OnClickListener).

一个例子:

CharSequence colors[] = new CharSequence[] {"red", "green", "blue", "black"};

AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Pick a color");
builder.setItems(colors, new DialogInterface.OnClickListener() {
    @Override
    public void onClick(DialogInterface dialog, int which) {
        // the user clicked on colors[which]
    }
});
builder.show();

输出(在Android 4.0.3上):

The output (on Android 4.0.3):

(背景图不包括。;))

(Background map not included. ;))

这篇关于Android:创建一个包含多个选择选项的弹出窗口的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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