WPF：创建一个对话/提示 [英] WPF: Create a dialog / prompt

问题描述

我需要创建一个包含TextBox的对话框/提示符以供用户输入。我的问题是，确认对话框后如何获取文本？通常我会为一个类保存一个属性的文本。不过我想用XAML设计对话框。所以我会以某种方式扩展XAML代码来将TextBox的内容保存在一个属性中 - 但是我猜想纯粹的XAML是不可能的。什么是最好的方式来实现我想做的事情？如何构建可以从XAML定义的对话框，但仍然可以以某种方式返回输入？感谢任何提示！

I need to create a Dialog / Prompt including TextBox for user input. My problem is, how to get the text after having confirmed the dialog? Usually I would make a class for this which would save the text in a property. However I want do design the Dialog using XAML. So I would somehow have to extent the XAML Code to save the content of the TextBox in a property - but I guess that's not possible with pure XAML. What would be the best way to realize what I'd like to do? How to build a dialog which can be defined from XAML but can still somehow return the input? Thanks for any hint!

推荐答案

负责任的答案将是我建议为对话框建立一个ViewModel并使用两个在TextBox上的数据绑定，以便ViewModel有一些ResponseText属性或什么不。这很容易做，但可能是过度的。

The "responsible" answer would be for me to suggest building a ViewModel for the dialog and use two-way databinding on the TextBox so that the ViewModel had some "ResponseText" property or what not. This is easy enough to do but probably overkill.

实用的答案是给你的文本框一个x：名称，使它成为一个成员并公开文本作为您代码中的代码属性，如下所示：

The pragmatic answer would be to just give your text box an x:Name so that it becomes a member and expose the text as a property in your code behind class like so:

<!-- Incredibly simplified XAML -->
<Window x:Class="MyDialog">
   <StackPanel>
       <TextBlock Text="Enter some text" />
       <TextBox x:Name="ResponseTextBox" />
       <Button Content="OK" Click="OKButton_Click" />
   </StackPanel>
</Window>

然后在你的代码背后...

Then in your code behind...

partial class MyDialog : Window {

    public MyDialog() {
        InitializeComponent();
    }

    public string ResponseText {
        get { return ResponseTextBox.Text; }
        set { ResponseTextBox.Text = value; }
    }

    private void OKButton_Click(object sender, System.Windows.RoutedEventArgs e)
    {
        DialogResult = true;
    }
}

然后使用它...

var dialog = new MyDialog();
if (dialog.ShowDialog() == true) {
    MessageBox.Show("You said: " + dialog.ResponseText);
}

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