生成唯一的颜色 [英] Generate unique colours

问题描述

我想提请一些数据到纹理：在连续多个项目。他们不是为了创建的，他们都可能是不同的大小（想到一个内存堆）。每个数据项是一个小矩形，我希望能够区分它们分开，所以我想他们每个人都有独特的色彩。

I want to draw some data into a texture: many items in a row. They aren't created in order, and they may all be different sizes (think of a memory heap). Each data item is a small rectangle and I want to be able to distinguish them apart, so I'd like each of them to have a unique colour.

现在我可以只使用兰特（）来生成RGB值，并希望他们都不同，但我怀疑我不会在RGB空间分配好。难道还有比这更好的办法吗？例如。什么是通过不同颜色的循环之前，他们（几乎）重复的好方法？

Now I could just use rand() to generate RGB values and hope they are all different, but I suspect I won't get good distribution in RGB space. Is there a better way than this? E.g. what is a good way of cycling through different colours before they (nearly) repeat?

的颜色不必匹配中的项目的任何数据。我只是希望能够看多值，看看它们是不同的，因为它们是相邻的。

The colours don't have to match with any data in the items. I just want to be able to look at many values and see that they are different, as they are adjacent.

我会想办法的，但我认为这是一个有趣的问题。 ：）

I could figure something out but I think this is an interesting question. :)

推荐答案

使用RGB颜色模式是不是一个好办法，以获得良好的色彩搭配。最好是用另一种颜色模型来生成你的颜色，然后从颜色模式为RGB转换。

Using the RGB color model is not a good way to get a good color mix. It's better to use another color model to generate your color, and then convert from that color model to RGB.

我建议你 HSV或HSL 颜色模式代替，特别是要改变< A HREF =htt​​p://en.wikipedia.org/wiki/Hue>色相。

I suggest you the HSV or HSL color model instead, in particular you want to vary the Hue.

如果你想要使用X不同的颜色值，它们各不相同，从0到360的360步长的X分。

If you want X different color values, vary them from 0 to 360 with a step size of 360 divided by X.

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