迭代字数值 [英] Iterating over dict values

问题描述

如果我想迭代存储在元组中的字典值。

If i would like to iterate over dictionary values that are stored in a tuple.

我需要返回持有CI值的对象，我假设我需要某种for循环：

i need to return the object that hold the "CI" value, i assume that i will need some kind of a for loop :

z = {'x':(123,SE,2,1),'z':(124,CI,1,1)}
for i, k in db.z:
    for k in db.z[i]:
        if k == 'CI':
            return db.z[k]

在这里，一个参考点是好的。

i am probably missing something here, a point of reference would be good.

如果有一个更快的方式这样做，这将大大有助于

if there is a faster way doing so it would all so help greatly

推荐答案

z = {'x':(123,"SE",2,1),'q':(124,"CI",1,1)}
for i in z.keys(): #reaching the keys of dict
    for x in z[i]: #reaching every element in tuples
        if x=="CI": #if match found..
            print ("{} holding {}.".format(i,x)) #printing it..

这可能会解决您的问题。

This might solve your problem.

输出：

>>> 
q holding CI.
>>> 

编辑您的评论：

def func(*args):
    mylist=[]
    z = {'x':(123,"SE",2,1),'q':(124,"CI",1,1)}
    for x,y in z.items():
        for t in args:
            if t in y:
                mylist.append(x)
    return mylist
print (func(1,"CI"))

输出：

>>> 
['q', 'q', 'x']
>>>  

Hope this is what you want, otherwise first method is already printing all keys, example output:

if x==1 or x=="CI":

>>> 
x holding 1.
q holding CI.
q holding 1.
q holding 1.
>>> 

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