范围作为Python中的字典键 [英] Range as dictionary key in Python

问题描述

所以，我有一个想法，我可以使用一系列数字作为字典中单个值的键。

So, I had an idea that I could use a range of numbers as a key for a single value in a dictionary.

我写了下面的代码，但是我不能让它上班是否有可能？

I wrote the code bellow, but I cannot get it to work. Is it even possible?

    stealth_roll = randint(1, 20)
    # select from a dictionary of 4 responses using one of four ranges.
    ## not working.
    stealth_check = {
                    range(1, 6) : 'You are about as stealthy as thunderstorm.',
                    range(6, 11) : 'You tip-toe through the crowd of walkers, while loudly calling them names.',
                    range(11, 16) : 'You are quiet, and deliberate, but still you smell.',
                    range(16, 20) : 'You move like a ninja, but attracting a handful of walkers was inevitable.'
                    }

    print stealth_check[stealth_roll]

推荐答案

感谢大家的回应。我一直在偷走，我想出了一个很适合我目的的解决方案。它最类似于@PaulCornelius的建议。

Thank you everyone for your responses. I kept hacking away, and I came up with a solution that will suit my purposes quite well. It is most similar to the suggestions of @PaulCornelius.

stealth_roll = randint(1, 20)
# select from a dictionary of 4 responses using one of four ranges.
# only one resolution can be True. # True can be a key value.

def check(i, a, b): # check if i is in the range. # return True or False
    if i in range(a, b):
        return True
    else:
        return False
### can assign returned object as dictionary key! # assign key as True or False.
stealth_check = {
                check(stealth_roll, 1, 6) : 
                'You are about as stealthy as a thunderstorm.',
                check(stealth_roll, 6, 11) : 
                'You tip-toe through the crowd of walkers, while loudly calling them names.',
                check(stealth_roll, 11, 16) : 
                'You are quiet, and deliberate, but still you smell.',
                check(stealth_roll, 15, 21) : 
                'You move like a ninja, but attracting a handful of walkers was inevitable.'
                }

print stealth_check[True] # print the dictionary value that is True.

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