根据范围获取子字典 [英] Get the subdictionary based on range

问题描述

我有一个字母，它具有坐标对作为键：ie：

I have a dictionary which has coordinate pairs as a keys: i.e.:

d = {(15,21): "value1", (7,45): "value2", (500,321): "value3",...}

现在我需要返回键位于一定范围内的元素的子字典：
例如：（6:16,20:46）的范围应该返回以下字典：
d = {（15,21）：Value1，（7,45）：value2} 如果该范围内没有其他元素。
有没有预定义的字典功能呢？你有什么建议吗？

Now I need to return a sub dictionary of the elements where the keys are within a certain range: for example: the range of (6:16, 20:46) should return the following dictionary: d = {(15,21): "Value1", (7,45): value2} if there was no other element in that range. Is there any predefined dictionary function to do that? ..or do you have any other suggestions?

Thx

推荐答案

这里有一种方法

d = {(15,21): "value1", (7,45): "value2", (500,321): "value3"}
x1, x2, y1, y2 = 6, 16, 20, 46 
dict((k,v) for k, v in d.iteritems() if x1<k[0]<x2 and y1<k[1]<y2)

Python 2.7已经添加了字典推导。最后一行变得更可读：

Python 2.7 has added dictionary comprehensions. The last line becomes more readable:

{k: v for k, v in d.iteritems() if x1<k[0]<x2 and y1<k[1]<y2}

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