如何仅在字典中存储一个键的3个值？蟒蛇 [英] How to only store 3 values for a key in a dictionary? Python

问题描述

所以我试图只允许程序只存储每个键（名称）的最后3个分数（值），但是我遇到一个问题，程序只存储3个分数，然后不更新最后3个或程序附加

So I tried to only allow the program to store only last 3 scores(values) for each key(name) however I experienced a problem of the program only storing the 3 scores and then not updating the last 3 or the program appending more values then it should do.

我到目前为止的代码：

    #appends values if a key already exists
    while tries < 3:
        d.setdefault(name, []).append(scores)
        tries = tries + 1

推荐答案

虽然我不能完全理解你的问题，但我从中得出的概念是，你只想在列表中存储最后三个分数。这是一个简单的任务。

Though I could not fully understand your question, the concept that I derive from it is that, you want to store only the last three scores in the list. That is a simple task.

d.setdefault(name,[]).append(scores)
if len(d[name])>3:
    del d[name][0]

该代码将检查列表的长度是否超过3。如果超过，则删除第一个元素（在最后三个元素之前添加的元素）

This code will check if the length of the list exceeds 3 for every addition. If it exceeds, then the first element (Which is added before the last three elements) is deleted

这篇关于如何仅在字典中存储一个键的3个值？蟒蛇的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！