循环上一个字典（以前的值）python [英] loop on a dictionary (previous values) python

问题描述

我有一个将概率与char相关联的字典

I have a dictionary associating a probability to a char

d = {'a': 0.2, 'b': 0.3, 'c': 0.4, 'd':0.1}

我正在寻找一种方式将每个字符的相关联的频率分布的最低值。所以每个字符都必须与之前的字符相关联。
我知道字典没有订购，但它应该返回类似于

And I am searching a way to associate to each char the lowest value of his frequency distribution. So every char must be associated to the sum of the previous ones. I know dictionary are not ordered but it should return something like

ddist = {'a': 0, 'b': 0.2, 'c': 0.5, 'd': 0.9}

循环，但我没有找到一种方法来获取以前的值...

I tried with a loop but I did not find a way to get the previous values...

任何想法？

推荐答案

您可以简单地迭代一个排序版本的密钥：

You can simply iterate over a sorted version of the keys:

d = {'a': 0.2, 'b': 0.3, 'c': 0.4, 'd':0.1}
ddist = {}
t = 0
for key in sorted(d):
    ddist[key] = t
    t += d[key]

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