将用户输入转换为列表名称 [英] Convert User Input into a List name

问题描述

这是我到目前为止：

TotalLists=int(input("How many Lists are you making?"))
TotalListsBackup=TotalLists
Lists=[]

while TotalLists>0:
  ListName=input("What would you like to call List Number "+str(TotalLists))
  Lists.append(ListName)
  TotalLists=TotalLists-1

TotalLists=TotalListsBackup-1

while TotalLists>=0:
  Lists[TotalLists] #I would like to create actual lists out of the list names at this step but I dont know how...
  TotalLists=TotalLists-1

TotalLists=TotalListsBackup-1

print("Here are your Lists: ")

while TotalLists>=0:
  print(Lists[TotalLists])
  TotalLists=TotalLists-1

我想要能够：

• 在列表名称之间创建一个列表


• 能够使用户想要的列表的代码没有cap

考试我想输入：Grocery，
代码将创建一个名为Called Grocery

For example, I want to input: Grocery, The code will create a list Called Grocery

解决方案我有想到：

• 数组？ （我从来没有使用过，我对Python编程很新，我不知道太多）

• Arrays? (I have never used them, I am very new to Python Programming and I dont know too much)

列表列表？ （不知道该怎么做，看起来，但没有得到直接的答案）

Lists of Lists? (Not sure how to do that. Looked it up, but didn't get a straight answer)

使用变量，创建一个名称如下所示的列表：

Using Variables, Creating a list with a name like:

List1[]

并有变量调用：

    List1Name=input("What would you like to call list 1?") 

我不知道如何创建一个

如果您有任何问题，请问，因为我知道我不善于解释。

If you have any questions please ask, for I know I am not good at explaining.

推荐答案

有趣的是，你标记了这个问题字典，但没有在你的帖子中提到。有人告诉你使用字典吗？这正是你应该做的，像这样（假设TotalLists已经定义）：

It's interesting that you have tagged the question "dictionary" but didn't mention that in your post. Did somebody tell you to use a dictionary? That's exactly what you should be doing, like this (assume TotalLists is already defined):

d = {}

for _ in range(TotalLists):   # The same loop you have now
    ListName = input("whatever...")
    d[ListName] = []

最后，您有一个字典d，其中包含用户输入的密钥，以及空列表的值。字典条目数是TotalLists。我忽略了用户两次输入相同名称的可能性。

At the end of this you have a dictionary d containing keys that are the user-entered names, and values that are empty lists. The number of dictionary entries is TotalLists. I'm ignoring the possibility that the user will enter the same name twice.

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