“dir”的输出结果以Java控制 [英] Outputting result of "dir" to console in Java
本文介绍了“dir”的输出结果以Java控制的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想将dir命令的结果输出到java控制台。我已经在谷歌和这里看过,但没有一个例子适用于我,所以让我礼貌的这个帖子。
I want to output the result of the "dir" command to the java console. I have already looked on Google and here, but none of the examples work for me, thus making me rite this post.
我的代码如下:
try
{
System.out.println("Thread started..");
String line = "";
String cmd = "dir";
Process child = Runtime.getRuntime().exec(cmd);
//Read output
BufferedReader dis = new BufferedReader( new InputStreamReader(child.getInputStream() ));
while ((line = dis.readLine()) != null)
{
System.out.println("Line: " + line);
}
dis.close();
}catch (IOException e){
}
What am I doing wrong?
任何帮助都会很好。
提前感谢,
Darryl
推荐答案
- 你不能运行dir作为一个进程,您需要将其更改为
String cmd =cmd dir;
。 - 完全处理异常。在catch块中添加行
e.printStackTrace());
会告诉你我在(1)中写的内容。 不要忽略异常! - 您不处理错误流。这可能会导致您的程序挂起,处理错误流,并使用不同的流并行读取两个流(错误和输入)。
- You cannot run "dir" as a process, you need to change it to
String cmd = "cmd dir";
. - You don't handle the exception at all. adding the line
e.printStackTrace());
in the catch block would tell you what I wrote in (1). Never ignore exceptions! - You don't handle error stream. This might cause your program to hang, handle error stream and read from both streams (error and input) in parallel using different streams.
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