在java中打开windows资源管理器 [英] Open up windows explorer in java
问题描述
我一直在Stack Overflow寻找一个答案,但是找不到对我有用的答案。
I have been looking for an answer to this on Stack Overflow, but I couldn't find an answer that worked for me.
使用Java,如何创建一个按钮,将启动资源管理器窗口到指定的目录?如果可以的话,我该如何使其在OSX和Linux上工作?
Using Java, how do I create a button that will launch an Explorer Window to a specified directory? If this is possible, how do I make it work for OSX and Linux?
推荐答案
我不知道它在其他操作系统,但在Windows中,您可以使用这样的东西
I am not sure how it works in other OS but in Windows you can use something like this
Desktop.getDesktop().open(new File("c:\\"));
编辑
找到其他方式(从该答案中检查链接到FileExplorer类)。还可以使用 System.getProperty(os.name)
来确定操作系统。
Edit
Found another way (check link to FileExplorer class from that answer). Also you can use System.getProperty("os.name")
to determine operation system.
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