Bash编程与文件系统功能 [英] Bash programming with filesystem functions

问题描述

本周我一直很忙，试图围绕一个小的Bash程序，将CMS从一个服务器迁移到另一个服务器。这样做的重要原因是因为我有40多个这样做，需要及时完成这个工作，因此Bash的想法。

不用说，到目前为止我遇到了一些问题，但其中一个已经完全停止了我的开发，目录检查。

没有我尝试了几种方法，没有一个似乎工作真的。抓到是我必须通过ssh检查远程服务器上的文件夹。这里我的例子：

  ExSshRsa =〜/ .ssh / id_rsa 
 ExSshPort = 22 
 ExSshHost = localhost 
 ExRoot = / var / www / 
 echo -n验证根访问$ ExRoot ...
 SSHRoot ='ssh -i $ ExSshRsa -p $ ExSshPort $ ExSshHost [-d $ ExRoot] ||退出1'
 echo $ SSHRoot 
如果[$ SSHRoot-eq 0] 
然后
 echoOK
 else 
 echoFAIL 
 fi 
  

我得到错误： [：：integer expression expected

[或测试不会重新设置0是数值。

解决方案

将字符串作为参数传递给远程主机不是微不足道的;您需要使用阵列。一个测试示例：

  declare -a cmd =（触摸带空格的文件名）
 declare -a escaped_cmd 
 
 
 escaped_cmd + =（$（printf％q$ arg）
 done 
 ssh localhost 
 $$ { $ {escaped_cmd [@]}
 ssh localhost ls＃在单独的行上返回带空格的文件名
  

所以你的情况应该是：

  ExSshRsa =〜/ .ssh / id_rsa 
 ExSshPort = 22 
 ExSshHost = localhost 
 ExRoot = / var / www / 
 echo -n验证根访问$ ExRoot ...
 
 declare -a cmd =（'['-d'$ ExRoot']'）＃需要引用[，因为它是一个Bash特定的符号
 declare -a escaped_cmd 
 for arg$ {cmd [@ ]}
 do 
 escaped_cmd + =（$（printf％q$ arg））
 done 
 
 ssh -i $ ExSshRsa -p $ ExSshPort $ ExSshHost $ {escaped_cmd [@]}
如果[$？ -eq 0] 
然后
 echoOK
 else 
 echoFAIL
 fi 
  

I have been busy this week trying to wrap my head around a little Bash program to migrate a CMS from one server to another. The reasopn for this is because I have more tha 40 of these to do, and need to get it done in a timely manner, thus the Bash idea.

Needless to say, I have run into a couple of problems so far, but one of them has halted my development completetly, directory checking.

No I have tried a couple of methods and none of them seem to work really. The catch is that I have to check the folder on a remote server via ssh. Here my example:

ExSshRsa=~/.ssh/id_rsa
ExSshPort=22
ExSshHost=localhost
ExRoot=/var/www/
echo -n "Verifying Root access $ExRoot..."
SSHRoot='ssh -i $ExSshRsa -p $ExSshPort $ExSshHost [ -d $ExRoot ] || exit 1 '
echo $SSHRoot 
if [ "$SSHRoot" -eq 0 ]
    then
        echo "OK"
    else
        echo "FAIL"
fi

I get the Error: [: : integer expression expected

Does the [ or test not resturn a 0 which is numerical. ?

解决方案

Passing strings as arguments to a remote host is not trivial; you need to use arrays. A test example:

declare -a cmd=(touch "file name with spaces")
declare -a escaped_cmd
for arg in "${cmd[@]}"
do
    escaped_cmd+=($(printf %q "$arg"))
done
ssh localhost "${escaped_cmd[@]}"
ssh localhost ls # Should return "file name with spaces" on a separate line

So your case should be:

ExSshRsa=~/.ssh/id_rsa
ExSshPort=22
ExSshHost=localhost
ExRoot=/var/www/
echo -n "Verifying Root access $ExRoot..."

declare -a cmd=( '[' -d "$ExRoot" ']' ) # Need to quote "[" since it's a Bash-specific symbol
declare -a escaped_cmd
for arg in "${cmd[@]}"
do
    escaped_cmd+=($(printf %q "$arg"))
done

ssh -i $ExSshRsa -p $ExSshPort $ExSshHost "${escaped_cmd[@]}"
if [ $? -eq 0 ]
then
    echo "OK"
else
    echo "FAIL"
fi

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